Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
Based on the information from your ICE Table (Part 1) and the Kc expression (Part 2), solve for the equilibrium concentration of H2O

Transcribed Image Text:Question 11 of 25
Predict the equilibrium concentration of H₂O in the reaction described below by
constructing an ICE table, writing the equilibrium constant expression, and solving for
the equilibrium concentration. Complete Parts 1-3 before submitting your answer.
2 H:S(g) + SO:(g) = 3 S(s) + 2 H:O(g)
NEXT
The reaction mixture initially contains 0.050 M H.S and 0.050 M SO.. Fill in the ICE table with the
appropriate value for each involved species to determine the concentrations of all reactants and
products.
Initial (M)
Change (M)
Equilibrium (M)
-31
0.025-2x
0
0.050x
0.025 +3
2 H₂S(g)
0.050
0.050+2x
0.025-x
+
+X
SO:(g)
0.050+ 3x
0.025-2x
+2x
0.050-
0.025-3
a
3 S(s)
+3x
0,050-2x
+
0.050-3
2 H.O(g)
RESET
-2x
0.025.
>
![Predict the equilibrium concentration of H₂O in the reaction described below by
constructing an ICE table, writing the equilibrium constant expression, and solving for
the equilibrium concentration. Complete Parts 1-3 before submitting your answer.
2 H.S(g) + SO:(g) = 3 S(s) + 2 H:O(g)
PREV
The value of Kc is 1.79 at a certain temperature.Using the data from your ICE Table (Part 1), construct
the expression for the equilibrium constant, Kc. Each reaction participant must be represented by one
tile. Do not combine terms.
[1]
E
(3xP
10.050-31
[xp
10.050-x1
10.050-3.1
K₁ =
Question 11 of 25
kxp
[0.050-x)
= 1.79
[2x]
[2xP
10.050-2x1
10.050-x)
[2x]"
10 050-21
NEXT
[3x]
10 050-2
RESET
(3x)
10.050-3x1](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F47a93c5c-68bf-41cc-bf52-8a28b4b1bd34%2F2b4b540a-7906-428f-81ce-02d13cd904bf%2Fwp4oa09_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Predict the equilibrium concentration of H₂O in the reaction described below by
constructing an ICE table, writing the equilibrium constant expression, and solving for
the equilibrium concentration. Complete Parts 1-3 before submitting your answer.
2 H.S(g) + SO:(g) = 3 S(s) + 2 H:O(g)
PREV
The value of Kc is 1.79 at a certain temperature.Using the data from your ICE Table (Part 1), construct
the expression for the equilibrium constant, Kc. Each reaction participant must be represented by one
tile. Do not combine terms.
[1]
E
(3xP
10.050-31
[xp
10.050-x1
10.050-3.1
K₁ =
Question 11 of 25
kxp
[0.050-x)
= 1.79
[2x]
[2xP
10.050-2x1
10.050-x)
[2x]"
10 050-21
NEXT
[3x]
10 050-2
RESET
(3x)
10.050-3x1
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