Based on the graph below, what was the acceleration of the object between 0.0 s and 5.0 s? Round your answer to 3 sig figs. 16.0 0.0s,120 ms) 12.0 (50s, 0.0 m's) - time (s) 4.0 0.0 0.0 0.5 1.0 1.5 20 2.5 3.0 3.5 4.0 4.5 5.0 -2.00 m/s/s -2.40 m/s/s 3.20 m/s/s d. -2.80 m/s/s 2.00 m/s/s f 2.80 m/s/s -3.20 m/s/s 2.40 m/s/s (s/1) fipopa
Displacement, Velocity and Acceleration
In classical mechanics, kinematics deals with the motion of a particle. It deals only with the position, velocity, acceleration, and displacement of a particle. It has no concern about the source of motion.
Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, for example, from side to side or up and down. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Non-contact sensors such as LVDTs and other linear location sensors can calculate linear displacement. Linear displacement is usually measured in millimeters or inches and may be positive or negative.
![**Question:**
Based on the graph below, what was the acceleration of the object between 0.0 s and 5.0 s? Round your answer to 3 significant figures.
**Graph Description:**
- The graph displays velocity (in m/s) on the vertical axis and time (in seconds) on the horizontal axis.
- It shows a linear decrease from (0.0 s, 12.0 m/s) to (5.0 s, 0.0 m/s).
- The velocity decreases steadily to zero over the 5-second interval.
**Answer Choices:**
- a: -2.00 m/s²
- b: -2.40 m/s²
- c: 3.20 m/s²
- d: -2.80 m/s²
- e: 2.00 m/s²
- f: 2.80 m/s²
- g: -3.20 m/s²
- h: 2.40 m/s²
**Explanation:**
To find the acceleration, use the formula:
\[ \text{Acceleration} = \frac{\Delta \text{Velocity}}{\Delta \text{Time}} \]
\[ \Delta \text{Velocity} = 0.0 \, \text{m/s} - 12.0 \, \text{m/s} = -12.0 \, \text{m/s} \]
\[ \Delta \text{Time} = 5.0 \, \text{s} - 0.0 \, \text{s} = 5.0 \, \text{s} \]
\[ \text{Acceleration} = \frac{-12.0 \, \text{m/s}}{5.0 \, \text{s}} = -2.40 \, \text{m/s}^2 \]
The correct answer is **b: -2.40 m/s²**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F320d91d8-67dc-45b8-8fab-c90fdb72c30d%2F3f4e2320-50de-4c97-8b7c-670e0e996abb%2Fjurioj_processed.jpeg&w=3840&q=75)
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