Based on the following data: Solution Volume of 1.0 M CH3COOH solution Experimental conductivity Corrected conductivity 4.00 419 414 B. 10.00 712 707 Using the data given, calculate the following: 1. Concentration after dilution of each solution using this formula: CIV1=czv2 2. molar conductivity of each solution using this formula molar conductivity = corrected conductivity concentration of solution in molanity 3. Fraction ionized using this formula: fraction ionized = molar conductivity/3.955x10s 4. Concentration of all species present in each solution. 5. pH of the solution 6. lonization constant of acetic acid

Based on the following data: Solution Volume of 1.0 M CH3COOH solution Experimental conductivity Corrected conductivity 4.00 419 414 B. 10.00 712 707 Using the data given, calculate the following: 1. Concentration after dilution of each solution using this formula: CIV1=czv2 2. molar conductivity of each solution using this formula molar conductivity = corrected conductivity concentration of solution in molanity 3. Fraction ionized using this formula: fraction ionized = molar conductivity/3.955x10s 4. Concentration of all species present in each solution. 5. pH of the solution 6. lonization constant of acetic acid

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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What volume of a 4.00 × 10-4 M FeSCN²+ solution would be needed to prepare 50.0 mL of a 7.20 × 10-5 M solution? O A. 20.0 mL O B. 278 mL O C. 5.56 mL O D. 9.00 mL O E. 3.60 mL