Based on the data shown below, calculate the regression line (each value to two decimal places)ˆy= + xxy111.88215.86317.44420.52522623.18725.36826.24930.621029.71133.381234.761338.741437.521541.5

Solution-: We have following table: X Y 1 11.88 2 15.86 3 17.44 4 20.52 5 22 6 23.18…

Answered: Based on the data shown below,…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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x	y
1	11.88
2	15.86
3	17.44
4	20.52
5	22
6	23.18
7	25.36
8	26.24
9	30.62
10	29.7
11	33.38
12	34.76
13	38.74
14	37.52
15	41.5

Similar questions

The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 40inches. Is the result close to the actual weight of 352pounds? Use a significance level of 0.05.a. Chest size (inches) 41 54 44 55 39 51 Weight (pounds) 328 528 418 580 296 503 a.What is the regression equation? b. The best predicted weight for a bear with a chest size of 39 inches is _______pounds.
Based on the data shown below, calculate the regression line (each value to two decimal places)y = x + x y 1 34.8 2 30.92 3 29.44 4 24.46 5 21.18 6 18.2 7 15.72 8 15.44 9 13.56 10 10.68 11 5.3
Based on the data shown below, calculate the regression line and the correlation coefficient. Round each value to three decimal places. y = 14.43 15.86 21.09 4 23.42 22.35 6. 25.08 29.31 8 31.54 9. 31.97 10 36.3 11 39.93 一 N
Based on the data shown below, calculate the regression line (each value to at least two decimal places)y = x + x y 4 21.44 5 22.35 6 21.56 7 22.47 8 21.28 9 24.69 10 22.3 11 25.71 12 26.82 13 26.63 14 25.44 15 25.85 16 27.36
Based on the data shown below, calculate the regression line (each value to two decimal places)y = x + x y 5 28.76 6 27.85 7 25.44 8 25.13 9 23.52 10 20.01 11 18
Run a regression analysis on the following bivariate set of data with y as the response variable. x y 43.2 -8.5 114.8 171 73.3 87.5 58.4 57.9 68.2 37.2 70.6 90.4 61.4 82.1 87.1 79.6 58 -9.2 78.4 77.2 80.5 87.3 64.1 22.9 54.3 32 Verify that the correlation is significant at an α=0.05α=0.05. If the correlation is indeed significant, predict what value (on average) for the explanatory variable will give you a value of 20.7 on the response variable.What is the predicted explanatory value?x = (Report answer accurate to one decimal place.)
Based on the data shown below, calculate the regression line (each value to two decimal places)y = x + x y 1 9.42 2 13.44 3 17.06 4 18.38 5 22.5 6 21.42 7 27.64 8 29.66
Based on the data shown below, calculate the regression line (each value to two decimal places)y = x y 2 17.72 3 19.58 4 21.24 5 22.6 6 25.56 7 28.62 8 30.78 9 31.74 10 36.4 11 35.96 12 38.62 13 42.18 14 43.14
Based on the data shown below, calculate the regression line (each value to two decimal places) %3D y 13.28 13.41 13.94 8. 10.37 9. 13.7 10 11.03 11 12.46 12 9.99 13 8.82 14 10.55 15 9.18 16 9.81 17 9.84 18 9.47 19 9.2 670

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Based on the data shown below, calculate the regression line (each value to two decimal places) ˆy= + x x y 1 11.88 2 15.86 3 17.44 4 20.52 5 22 6 23.18 7 25.36 8 26.24 9 30.62 10 29.7 11 33.38 12 34.76 13 38.74 14 37.52 15 41.5