Based on the balance equation convert the starting mass (g) of Potassium Chlorate (from the data table in the picture) to gram of the product in the test tube. (Use the three steop stoichiometry process) How much product you should be able to make in this reaction-theoretical yield. Balanced equation: 2 KIO3 = 2 KCI + 3O2 Potassium chlorate, Potassium chloride + diatomic oxyen
Based on the balance equation convert the starting mass (g) of Potassium Chlorate (from the data table in the picture) to gram of the product in the test tube. (Use the three steop stoichiometry process) How much product you should be able to make in this reaction-theoretical yield. Balanced equation: 2 KIO3 = 2 KCI + 3O2 Potassium chlorate, Potassium chloride + diatomic oxyen
Introductory Chemistry: A Foundation
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ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter9: Chemical Quantities
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Based on the balance equation convert the starting mass (g) of Potassium Chlorate (from the data table in the picture) to gram of the product in the test tube. (Use the three steop stoichiometry process) How much product you should be able to make in this reaction-theoretical yield.
Balanced equation: 2 KIO3 = 2 KCI + 3O2
Potassium chlorate, Potassium chloride + diatomic oxyen
![Mass of empty test tube
olege
1935 a
Potassium chlorate: 1.01g was measured out and placed into the test tube
Mass of Test tube + product after heating:
College
Na A
1986 a](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb0a0d5e1-1f83-455d-b96a-2a86811e45af%2F8682aa71-ec5f-4d28-8493-b20444f79727%2Fu6kxby9_processed.png&w=3840&q=75)
Transcribed Image Text:Mass of empty test tube
olege
1935 a
Potassium chlorate: 1.01g was measured out and placed into the test tube
Mass of Test tube + product after heating:
College
Na A
1986 a
![Mass of empty Test tube:
19.36g
Mass of Potassium chlorate used:
1.01g
Mass of product after heating+test tube:
19.86g
Mass of product after heating:
0.50g
SOLVE: (subtract mass of empty test tube)=actual yield](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb0a0d5e1-1f83-455d-b96a-2a86811e45af%2F8682aa71-ec5f-4d28-8493-b20444f79727%2Fpvwjlaf_processed.png&w=3840&q=75)
Transcribed Image Text:Mass of empty Test tube:
19.36g
Mass of Potassium chlorate used:
1.01g
Mass of product after heating+test tube:
19.86g
Mass of product after heating:
0.50g
SOLVE: (subtract mass of empty test tube)=actual yield
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