Based on historical data, your manager believes that 33% of the company's orders come from first-time customers. A random sample of 69 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is greater than than 0.38? Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations. Answer =| 0.9998 X o 0.1885 (Enter your answer as a number accurate to 4 decimal places.)

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Chapter1: Starting With Matlab
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First picture is the problem, second is my work. please tell me where i am going wrong.  

Based on historical data, your manager believes that 33% of the company's orders come from first-time
customers. A random sample of 69 orders will be used to estimate the proportion of first-time-customers.
What is the probability that the sample proportion is greater than than 0.38?
Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach
and calculations.
Answer =
0.9998 X o 0.1885 (Enter your answer as a number accurate to 4 decimal places.)
Transcribed Image Text:Based on historical data, your manager believes that 33% of the company's orders come from first-time customers. A random sample of 69 orders will be used to estimate the proportion of first-time-customers. What is the probability that the sample proportion is greater than than 0.38? Note: You should carefully round any z-values you calculate to 4 decimal places to match wamap's approach and calculations. Answer = 0.9998 X o 0.1885 (Enter your answer as a number accurate to 4 decimal places.)
graik Han 0.33
R033 n3Co4 9=0.67 x >0.38
np=69(0.33) = 2237 25/
ng= 69(0,67) = 46.2325/
42 M=np=D22.37
69(0.235)(0.16
= 3,90
St P(x>0.38)=P(xx0.38 -0.5)=0.88
%3D
nomalcelfl0.88,Eaa, 22.77,3.90 = 0.9999
0.1865
Transcribed Image Text:graik Han 0.33 R033 n3Co4 9=0.67 x >0.38 np=69(0.33) = 2237 25/ ng= 69(0,67) = 46.2325/ 42 M=np=D22.37 69(0.235)(0.16 = 3,90 St P(x>0.38)=P(xx0.38 -0.5)=0.88 %3D nomalcelfl0.88,Eaa, 22.77,3.90 = 0.9999 0.1865
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