Based on experience, it is assumed that 60% of the customers of EDSA Sang Hotel are foreigners. random sample of 80 registered guests of the hotel, 60 turned out to be foreigners. Test the 60% fig using an alpha of 0.05. Р n Sample p Critical Z value Conclusion: 60% 80 q X alpha 60 5%
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- Unfortunately, arsenic occurs naturally in some ground water. A mean arsenic level of u = 8 parts per billion (ppb) is considered safe for agricultural use. A well in Los Banos is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 37 tests gave a sample mean of = 7.3ppb arsenic. It is known that o = 1.9 ppb for this type of data. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use the classical approach. Use a = 0.01 What is the Decision (step 5) for this problem? There is not sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los Banos well is less than 7.3 ppb. O There is sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los Banos well is less than 8.0 ppb. There is not sufficient evidence at the 0.01 level of significance to show the mean arsenic level in the Los Banos well is less than 8.0 ppb. O There is…Dr. Romanoff reported the following in a journal: “F (5, 106) = 10.09, p = .04.” Should Dr. Romanoff state that there are significant differences among the variable means at a .05 alpha level?andres asked if there is a relationship between the quality of sneakers worn by a sample of 20 volleyball players and their average number of point scored per game. he computed r= +.21 and immediately claimed he had evidence that better-quality sneakers are related to better performance (a) is his claim correct? why? (b) what are Ho and Ha? (c) with alpha=.05, what is rcrit ?
- Do types of crimes reported on television newscasts differ by the age of the criminals? A researcher uses her dvr to record the local television news for a 2-week period of time. She records the types of crimes and notes the age of the offender. Conduct a chi-square test (alpha = .05) of the null hypothesis that televised offense type does not vary by age group of offender. Offense type Young middle age older violent 27 10 3 property 14 12 11 sex 7 9 5 Report the obtained chi-square, df, and critical chi-square. Report your findings based on the null hypothesis.A clinical study was conducted on a medicine and the data obtained as follows: calculate Sensitivity Diseased •True Positive: 1000 •True negative: 50 Non diseased •True positive: 100 •True negative: 800A clinical trial is planned to compare an experimental medication designed to lower blood pressure to a pla- cebo. Before starting the trial, a pilot study is conducted involving seven participants. The objective of the study is to assess how systolic blood pressure (SBP) changes over time if left untreated. SBP is measured at baseline and again 4 weeks later. Is there a statistically significant difference in SBP over time? Run the test at a 5% level of significance. Baseline 120 145 130 160 152 143 126 Four weeks 122 142 135 158 155 140 130 how do I solve this in excel?
- At age 9 the average weight for both boys and girls are exactly the same. A random sample of 9 year olds gave the following results.... Boys: Girls:Sample Size: 65 50Mean weight (lbs): 130 125Pop. Variance: 120 130 At alpha 0.05, do the data support the claim that there is a difference in heights?Patients with rheumatoid arthritis are at a greater risk of developing osteoporosis. The reasons are not well understood due to the difficulty in qualitatively assessing bone metabolism and mineral content. A researcher measures human calcitonin (HCT) levels in men with rheumatoidarthritis. The researcher randomly selects 43 men with rheumatoid arthritis and measured the mean HCT level of 33.8 pg/mL. Assume that HCT for individuals with rheumatoid arthritis follows a normal distribution with standard deviation σ = 23.6 pg/mL. 3. Create a 95% confidence interval for the population mean HCT.Patients with rheumatoid arthritis are at a greater risk of developing osteoporosis. The reasons are not well understood due to the difficulty in qualitatively assessing bone metabolism and mineral content. A researcher measures human calcitonin (HCT) levels in men with rheumatoidarthritis. The researcher randomly selects 43 men with rheumatoid arthritis and measured the mean HCT level of 33.8 pg/mL. Assume that HCT for individuals with rheumatoid arthritis follows a normal distribution with standard deviation σ = 23.6 pg/mL. 6. Describe the effect on your confidence interval if you increase or decrease the samplesize
- Patients with rheumatoid arthritis are at a greater risk of developing osteoporosis. The reasons are not well understood due to the difficulty in qualitatively assessing bone metabolism and mineral content. A researcher measures human calcitonin (HCT) levels in men with rheumatoidarthritis. The researcher randomly selects 43 men with rheumatoid arthritis and measured the mean HCT level of 33.8 pg/mL. Assume that HCT for individuals with rheumatoid arthritis follows a normal distribution with standard deviation σ = 23.6 pg/mL. 7. Describe a situation where a researcher would want to use a larger confidence level than 95% and a situation where a smaller confidence level would be preferred.Patients with rheumatoid arthritis are at a greater risk of developing osteoporosis. The reasons are not well understood due to the difficulty in qualitatively assessing bone metabolism and mineral content. A researcher measures human calcitonin (HCT) levels in men with rheumatoidarthritis. The researcher randomly selects 43 men with rheumatoid arthritis and measured the mean HCT level of 33.8 pg/mL. Assume that HCT for individuals with rheumatoid arthritis follows a normal distribution with standard deviation σ = 23.6 pg/mL. 4. Explain in detail what the 95% Confidence Interval for the mean HCT represents within this context.The average UQ student reports dedicating 8.5 hours per week to each 2-unit course. What is the approximate t obtained value for a group of 16 psychology students who study for a mean of 9.5 hours per week for each 2-unit course, where the estimated population variance is 3.68. Would this sample be considered significantly different from the population, applying an alpha level of 0.05? t = 0.48; the sample would be considered statistically significant t = 0.48; the sample would NOT be considered statistically significant t = 2.08; the sample would NOT be considered statistically significant t = 2.08; the sample would be considered statistically significant