how would you write an hypothesis and prediction from the given data? **Table 3: Results for Spot Assay Tests on Progeny of Unknown Parental Generation Flies**| Fly No. | AO Activity (+ / -) | Fly No. | AO Activity (+ / -) ||---------|---------------------|---------|---------------------|| 1 | - | 13 | + || 2 | - | 14 | - || 3 | - | 15 | - || 4 | - | 16 | - || 5 | + | 17 | + || 6 | - | 18 | - || 7 | + | 19 | + || 8 | - | 20 | - || 9 | - | 21 | - || 10 | - | 22 | + || 11 | + | 23 | + || 12 | + | 24 | + |**Explanation:**This table provides the results of a spot assay test focusing on AO (Antioxidant) activity in the progeny of an unknown parental generation of flies. Each row represents a different fly, identified by a unique fly number. The AO activity is indicated by a '+' for positive activity and '-' for negative activity. The data suggests variability in AO activity among the progeny. **Genetic Analysis Exercise****Based on all observations, hypothesize the genotypes of the parent flies, making sure to notate the alleles correctly.****Gene:** Aldox gene **Allele #1:** A0⁺ **Allele #2:** A0⁻ **Parental genotypes:** One parent is heterozygous, and another parent is homozygous for the recessive allele.**Hypothesis:** (Blank space for student input)**Prediction:** (Blank space for student input)

Name: how would you write an hypothesis and prediction from the given data?
Uploaded: 2024-03-20T06:43:04.000Z
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Description: how would you write an hypothesis and prediction from the given data? **Table 3: Results for Spot Assay Tests on Progeny of Unknown Parental Generation Flies**| Fly No. | AO Activity (+ / -) | Fly No. | AO Activity (+ / -) ||---------|---------------

The hypothesis is the explanation proposed on the basis of the previous observation or evidence of the results of the study. Hypothesis: From the given data one can hypothesize that the Aldox gene is the gene that shows the inheritance pattern which determines the enzyme aldehyde oxidase activity in the progeny. Aldoxx gene codes for the enzyme aldehyde oxidase. This enzyme expression depends on the presence of the dominant allele AO+, hence all the progeny which shows the activity as denoted by the + sign shows the AO inheritance or expression. While those progeny which doesn't show activity (denoted by -) lack the dominant allele and has the recessive allele AO-. Predictions: Thus, the genotypes of the progeny 1, 2, 3, 4, 6, 8, 9, 10, 14, 15, 16, 18, 20, 21 are AO-AO- While genotypes of progeny 5, 7, 11, 12, 13, 17, 19, 22, 23, 24 are AO+AO+ or AO+AO- Hence, the parental genotypes for the progenies can be AO+AO- and AO-AO- (one parent heterozygous and another homozygous recessive) or either AO+AO- and AO+AO-( both parents heterozygous)