Base on the given pka and structure of the vitamin A, predict what would happen to the messagewritten in NaNH2 (pKa 38) when sprayed with vitamin A?CompoundNH3Conjugate baseNH2pka38Select one:OHVitamin Aa.Invisible. Reaction is reactant favoredO b. Invisible. Reaction is product favored but no resonance structures○ c.Visible. Reaction is reactant favoredO d. Visible. Reaction is product favoredWhich of the following base is strong enough to deprotonate ethanol?16

Whether equilibrium lies on the right side or left side depends upon the acidity of the reactant and…

Base on the given pKa and structure of the vitamin A, predict what would happen to the message written in NaNH2 (pKa 38) when sprayed with vitamin A? Compound NH3 Conjugate base NH2 pKa 38 OH Vitamin A 0,0 16 Select one: a. Invisible. Reaction is reactant favored b. Invisible. Reaction is product favored but no resonance structures O c. Visible. Reaction is reactant favored d. Visible. Reaction is product favored

Base on the given pKa and structure of the vitamin A, predict what would happen to the message written in NaNH2 (pKa 38) when sprayed with vitamin A? Compound NH3 Conjugate base NH2 pKa 38 OH Vitamin A 0,0 16 Select one: a. Invisible. Reaction is reactant favored b. Invisible. Reaction is product favored but no resonance structures O c. Visible. Reaction is reactant favored d. Visible. Reaction is product favored

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Fill in the missing part of reactions below:
Dilute solution of unknown weak acid required 30 ml of 0.2 M NAOH to reach phenolphthalein end point. Calculate the molecular weight of the acid if sodium salt was found to weigh 0.3g, the reaction is one to one. O a. 50g/mole O b. 100g/mole O c. 200g/mole O d. 23g/mole
Which of the following explains why alpha-amino acids, the building blocks of proteins, are nearly 1000 times more acidic than aliphatic carboxylic acids? H3N. R. An a-amino acid An aliphatic acid pK, 5 pKa = 2 O Inductive effects of the aliphatic group destabilize the conjugate base. O Inductive effects of the amino group help stabilize the conjugate base. O Inductive effects of the aliphatic groups help stbilize the conjugate base. O Inductive effects of the amino group destabilize the conjugate base.
Please predict the products for each of the following reactions: Na A 2. PrBr 1. Na 1. TsCI, Py 2. NaBr, DMSO SOCI2, Py 6 8 Co 10 H-NⒸ CrO₂Cl B TSCI Py (pyridine) 6 2 OH LC 5 2. KI, DMF 1. MSCI, Et3N (base) с PCC H Na₂Cr₂O7 H₂SO4 HCI ZnCl₂ D OH
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Which molecule below has the lowest pKa? 0000 A B D OH A OH B C OH D OH
Which proton is the most likely to be removed when this molecule reacts with NaNH,? H (B) - (C) CH3 (A)→ H. H P) 0 a A Ob.B Oc.C O d.D nane 1000 auto.procton
4. structures. 4 1 -H 2 H- S Which numbered hydrogen has the lowest pKa? Explain your answer in words and by using H Н 3HS Spa Sp2 Sp3 HH 5
Consider the equilibrium equation below: Co(H2O)62+ (aq) + 4Cl- (aq) ⇌ CoCl42- (aq) + 6H2O When hydrochloric acid is added, to achieve equilibrium, [Co(H2O)62+] and [CoCl42-] will A. Decrease, increase respectively B. Increase, decrease respectively C. Decrease, decrease respectively D. Increase, increase respectively
8. Consider each reaction below carefully. Identify the acid and base on the reactant side of the reaction. Draw the expected product of a proton transfer between the acid and base. Estimate the pka of the acid and conjugate acid. Determine whether the reaction is product or reactant favored. a. b. C. d. OH @O HICI HO NaH 39
A. Draw the structure for compound X at pH=9. What is the charge of the molecule? B. Draw the structure for Compound X at pH=2. What is the charge of the molecule?
For this proton transfer reaction, draw in the appropriate product(s) and curved arrow(s). :0: H I I Ə. H 2.