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base line was measured in catenary in four lengths giving 30.126, 29.973, 30.066, and 22.536 meters. The differences of level were spectively 0.45, 0.60, 0.30, and 0.45 meters. The temperature during the observation was 10°C and the tension applied is 15 kg. The tape as standardized as 30 meters at 20°C, on the flat with a tension of 5 kg. The coefficient of expansion was 0.0000116 per °C, the weight of e tape is 1 kg, the cross-sectional area is 3 mm?, E=210×10³ N/mm²(210 kN/mm²), gravitational acceleration is g=9.80665 m/s²?. e total correction due to pull is meters ound your answer to six decimal places.) me total correction due to temperature is meters ound your answer to six decimal places.) me total correction due to sag is meters. ound your answer to six decimal places.) me total correction due to slope is ound your answer to six decimal places.) e total combined correction is meters. ound your answer to six decimal places if necessary.) ie correct length of the line is meters. ound your answer to four decimal places if necessary.) e normal tension is kilograms.

base line was measured in catenary in four lengths giving 30.126, 29.973, 30.066, and 22.536 meters. The differences of level were spectively 0.45, 0.60, 0.30, and 0.45 meters. The temperature during the observation was 10°C and the tension applied is 15 kg. The tape as standardized as 30 meters at 20°C, on the flat with a tension of 5 kg. The coefficient of expansion was 0.0000116 per °C, the weight of e tape is 1 kg, the cross-sectional area is 3 mm?, E=210×10³ N/mm²(210 kN/mm²), gravitational acceleration is g=9.80665 m/s²?. e total correction due to pull is meters ound your answer to six decimal places.) me total correction due to temperature is meters ound your answer to six decimal places.) me total correction due to sag is meters. ound your answer to six decimal places.) me total correction due to slope is ound your answer to six decimal places.) e total combined correction is meters. ound your answer to six decimal places if necessary.) ie correct length of the line is meters. ound your answer to four decimal places if necessary.) e normal tension is kilograms.

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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A base line was measured in catenary in four lengths giving 30.126, 29.973, 30.066, and 22.536 meters. The differences of level were respectively 0.45, 0.60, 0.30, and 0.45 meters. The temperature during the observation was 10°C and the tension applied is 15 kg. The tape was standardized as 30 meters at 20°C, on the flat with a tension of 5 kg. The coefficient of expansion was 0.0000116 per °C, the weight of the tape is 1 kg, the cross-sectional area is 3 mm?, E=210x103 N/mm?(210 kN/mm?), gravitational acceleration is g=9.80665 m/s?. The total correction due to pull is meters (Round your answer to six decimal places.) The total correction due to temperature is meters (Round your answer to six decimal places.) The total correction due to sag is meters. (Round your answer to six decimal places.) The total correction due to slope is (Round your answer to six decimal places.) The total combined correction is meters. (Round your answer to six decimal places if necessary.) The correct length of the line is meters. (Round your answer to four decimal places if necessary.) The normal tension is kilograms. (Round your answer to six decimal places.)
Transcribed Image Text:A base line was measured in catenary in four lengths giving 30.126, 29.973, 30.066, and 22.536 meters. The differences of level were respectively 0.45, 0.60, 0.30, and 0.45 meters. The temperature during the observation was 10°C and the tension applied is 15 kg. The tape was standardized as 30 meters at 20°C, on the flat with a tension of 5 kg. The coefficient of expansion was 0.0000116 per °C, the weight of the tape is 1 kg, the cross-sectional area is 3 mm?, E=210x103 N/mm?(210 kN/mm?), gravitational acceleration is g=9.80665 m/s?. The total correction due to pull is meters (Round your answer to six decimal places.) The total correction due to temperature is meters (Round your answer to six decimal places.) The total correction due to sag is meters. (Round your answer to six decimal places.) The total correction due to slope is (Round your answer to six decimal places.) The total combined correction is meters. (Round your answer to six decimal places if necessary.) The correct length of the line is meters. (Round your answer to four decimal places if necessary.) The normal tension is kilograms. (Round your answer to six decimal places.)
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