Barium chloride reacts with aluminum sulfate according to the equation: Al2(SO4)3 + 3BaCl2=’ 2AlCl3 + 3BaSO4. Calculate the maximum mass (theoretical yield) of AlCl3 that could be obtained when 6.00 mol of BaCl2 reacts with excess aluminum sulfate.  AlC3=133.3  BaCl2=208.23 Al2(SO4)3- 342.15

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