Barium chloride reacts with aluminum sulfate according to the equation: Al2(SO4)3 + 3BaCl2=’ 2AlCl3 + 3BaSO4. Calculate the maximum mass (theoretical yield) of AlCl3 that could be obtained when 6.00 mol of BaCl2 reacts with excess aluminum sulfate. AlC3=133.3 BaCl2=208.23 Al2(SO4)3- 342.15
Barium chloride reacts with aluminum sulfate according to the equation: Al2(SO4)3 + 3BaCl2=’ 2AlCl3 + 3BaSO4. Calculate the maximum mass (theoretical yield) of AlCl3 that could be obtained when 6.00 mol of BaCl2 reacts with excess aluminum sulfate. AlC3=133.3 BaCl2=208.23 Al2(SO4)3- 342.15
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter3: Chemical Reactions
Section: Chapter Questions
Problem 73QRT
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Question
Barium chloride reacts with aluminum sulfate according to the equation: Al2(SO4)3 + 3BaCl2=’ 2AlCl3 + 3BaSO4. Calculate the maximum mass (theoretical yield) of AlCl3 that could be obtained when 6.00 mol of BaCl2 reacts with excess aluminum sulfate.
AlC3=133.3
BaCl2=208.23
Al2(SO4)3- 342.15
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