Balance the following oxidation-reduction reaction as if it were to occur in a basic solution. I(aq) + CIO¯(aq) → I3¯(aq) + Cl¯(aq) HOW DO WE GET THERE? Since this reaction takes place in basic solution, add OH" ions to both sides of the balanced equation to eliminate the Ht ions. 2 OH (aq) + 2 H*(aq) + CIO"(aq) + 3 1"(aq) → I3-(aq) + Cl"(aq) + H2O(1) + 2 OH"(aq) How many H20 molecules does this form on the left side of the equation?

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Balance the following oxidation-reduction reaction as if it were to occur in a basic solution.
I(aq) + CIO (aq) → I3¬(aq) + CI"(aq)
HOW DO WE GET THERE?
Since this reaction takes place in basic solution, add OH- ions to both sides of the balanced equation to eliminate the H+ ions.
2 OH (aq) + 2 H*(aq) + CIO¯(aq) + 3 I"(aq) → I3 (aq) + CI (aq) + H20(1) + 2 OH¯(aq)
How many H20 molecules does this form on the left side of the equation?
Transcribed Image Text:Balance the following oxidation-reduction reaction as if it were to occur in a basic solution. I(aq) + CIO (aq) → I3¬(aq) + CI"(aq) HOW DO WE GET THERE? Since this reaction takes place in basic solution, add OH- ions to both sides of the balanced equation to eliminate the H+ ions. 2 OH (aq) + 2 H*(aq) + CIO¯(aq) + 3 I"(aq) → I3 (aq) + CI (aq) + H20(1) + 2 OH¯(aq) How many H20 molecules does this form on the left side of the equation?
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