Certain salts of benzoic acid have been used as food additives for decades. The potassium salt of benzoic acid, potassium benzoate, can be made by the action of potassium permanganate on toluene according to the following reaction (unbalanced): C7H8 + KMnO4 ® KC7H5O2 + MnO2 + KOH + H2O toluene potassium benzoate Balance the equation.What is the limiting reactant when 10.750 g of toluene react with 14.750 g of potassium permanganate?How much of the excess reactant remains after all of the limiting reactant is consumed?In an experiment using the masses of reactants listed above, 7.042 g of potassium benzoate was produced. What is the percent yield of that experiment?If the yield of potassium benzoate cannot realistically be expected to be more than 72.15%, what is the minimum number of grams of toluene needed to achieve this yield while producing 10.00 g of KC7H5O2?

(1) The balanced Chemical equation is - C7H8 + 2KMnO4 ---> KC7H5O2 + 2MnO2 + KOH + H2O…

Answered: Balance the equation. What is the…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Certain salts of benzoic acid have been used as food additives for decades. The potassium salt of benzoic acid, potassium benzoate, can be made by the action of potassium permanganate on toluene according to the following reaction (unbalanced):

C₇H₈ + KMnO₄ ® KC₇H₅O₂ + MnO₂ + KOH + H₂O

toluene potassium

benzoate

Balance the equation.
What is the limiting reactant when 10.750 g of toluene react with 14.750 g of potassium permanganate?
How much of the excess reactant remains after all of the limiting reactant is consumed?
In an experiment using the masses of reactants listed above, 7.042 g of potassium benzoate was produced. What is the percent yield of that experiment?
If the yield of potassium benzoate cannot realistically be expected to be more than 72.15%, what is the minimum number of grams of toluene needed to achieve this yield while producing 10.00 g of KC₇H₅O₂?

Expert Solution

Step 1

(1) The balanced Chemical equation is -

C₇H₈ + 2KMnO₄ ---> KC₇H₅O₂ + 2MnO₂ + KOH + H₂O

(C=7,H=8,K=2,Mn=2,O=8---> K=2,C=7,H=8,O=8,Mn=2)

(2) Molar mass of toluene = 92 g/mol

And, molar mass of KMnO₄ = 158 g/mol

Then, 10.750 gram toluene needed -

(10.750/92)×158×2 = 36.924 gram KMnO₄

But we have only 14.750 gram of potassium permanganate. Therefore limiting agent is KMnO₄.

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