BALANCE REDOX REACTION (USE THE LONG METHOD WITH CHECKINGS) Fe2+ + Cr Fe + Cr³+ CONTENT SHOULD BE THESE OXIDIZED REDUCED BASIC SOLUTION CHECKING

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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BALANCE REDOX REACTION
(USE THE LONG METHOD WITH
CHECKINGS)
2+
Fe²+ + Cr Fe + Cr³+
CONTENT SHOULD BE THESE
-
OXIDIZED
REDUCED
BASIC SOLUTION
CHECKING
2+
3) AI + NO₂ → A)
+5+4=1
↑
6
+5-2
Al + NO₂
oxidized:
A1 A1²+ + 2 e
A²:11A):1
0
V
oxidized, reduced oxidizing agent
reducing agent
ducking Al: 1
#:4
V2
1
+2
A/ ²+
+2-2=0
BASIC SOLUTION
ها : 0
t
+4-2=12
+ ND₂
Al 721²2e
2e + 4H+ + 2NO → 2ND ₂ + 2H₂P
AL + 26² + 4H+ + 2 NO₂ → A1 ²+ + 2 e ²³ + 2NO₂ + 2H₂O
| AL + 4H+ + 2 NO ₂² →→ 41 ²+ + 2NO₂ + 2H₂O Balanced in acidic solution
clacking AI:1
H: 4
0216=8
N²2
+4 -4 =0
↑
+4-2
-2
+ NO ₂
Al: T
H:4
N÷ 2
0:4+2=6
+2
Reduced:
et 2H+ + NO₂ → NO₂ + H₂D
V: 1
N = 1
0-83
H: 2
O
AL+ 4H+ + 2NO₂
A1²+ + 2NO₂ + 2H₂O
Al + 4H+ + 40H¯¯ + 2 NO ₂- → A1²+ + 2NO₂ + 2H₂0 + 40H-
Al + √₂ + 2 NO ₂- → A1 ²+ + 2NO₂ + 2H₂Q+40H-
2
| Al + 2 H₂O + 2NO3 →→ A1²+ + 2NO₂ + 40H - Balanced in basic solution
H:4
0²4+4=8
N÷2
Date :
0:3
H.2
+2-4-H-01
2 (e² + 2H² + NO₂- →-> NO ₂ + H₂0)
2e + 4H+ + 2NO3 → 2ND ₂ + 2H₂O
+2-4=VICTORY
Transcribed Image Text:BALANCE REDOX REACTION (USE THE LONG METHOD WITH CHECKINGS) 2+ Fe²+ + Cr Fe + Cr³+ CONTENT SHOULD BE THESE - OXIDIZED REDUCED BASIC SOLUTION CHECKING 2+ 3) AI + NO₂ → A) +5+4=1 ↑ 6 +5-2 Al + NO₂ oxidized: A1 A1²+ + 2 e A²:11A):1 0 V oxidized, reduced oxidizing agent reducing agent ducking Al: 1 #:4 V2 1 +2 A/ ²+ +2-2=0 BASIC SOLUTION ها : 0 t +4-2=12 + ND₂ Al 721²2e 2e + 4H+ + 2NO → 2ND ₂ + 2H₂P AL + 26² + 4H+ + 2 NO₂ → A1 ²+ + 2 e ²³ + 2NO₂ + 2H₂O | AL + 4H+ + 2 NO ₂² →→ 41 ²+ + 2NO₂ + 2H₂O Balanced in acidic solution clacking AI:1 H: 4 0216=8 N²2 +4 -4 =0 ↑ +4-2 -2 + NO ₂ Al: T H:4 N÷ 2 0:4+2=6 +2 Reduced: et 2H+ + NO₂ → NO₂ + H₂D V: 1 N = 1 0-83 H: 2 O AL+ 4H+ + 2NO₂ A1²+ + 2NO₂ + 2H₂O Al + 4H+ + 40H¯¯ + 2 NO ₂- → A1²+ + 2NO₂ + 2H₂0 + 40H- Al + √₂ + 2 NO ₂- → A1 ²+ + 2NO₂ + 2H₂Q+40H- 2 | Al + 2 H₂O + 2NO3 →→ A1²+ + 2NO₂ + 40H - Balanced in basic solution H:4 0²4+4=8 N÷2 Date : 0:3 H.2 +2-4-H-01 2 (e² + 2H² + NO₂- →-> NO ₂ + H₂0) 2e + 4H+ + 2NO3 → 2ND ₂ + 2H₂O +2-4=VICTORY
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