Balance and complete the following combustion reaction. Enter the sum of the balanced coefficients as your answer. Assign "blank" coefficients a value of 1. tetracarbon herahydride (g) + oxygen (g) –?

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**Balancing Combustion Reactions**

In this exercise, balance and complete the following combustion reaction. After balancing, enter the sum of the coefficients as your answer. If a coefficient is not explicitly listed (i.e., a "blank" coefficient), it is assigned a value of 1.

### Reaction:

- **Tetracarbon Hexahydride (g) + Oxygen (g) —> ?**

### Instructions:

1. Identify the chemical formula for tetracarbon hexahydride: This is commonly known as butane, with the formula \( C_4H_6 \).

2. Write the unbalanced combustion reaction: 
   \[ C_4H_6 (g) + O_2 (g) \rightarrow CO_2 (g) + H_2O (g) \]

3. Balance the equation:
   - Balance carbon atoms first: 
     \[ C_4H_6 (g) + O_2 (g) \rightarrow 4 CO_2 (g) + H_2O (g) \]

   - Balance hydrogen atoms next: 
     \[ C_4H_6 (g) + O_2 (g) \rightarrow 4 CO_2 (g) + 3 H_2O (g) \]

   - Finally, balance oxygen atoms:
     - Total O on right = \( 4 \times 2 + 3 \times 1 = 11 \)
     - Therefore, we balance by adjusting \( O_2 \):
     \[ C_4H_6 (g) + \frac{11}{2} O_2 (g) \rightarrow 4 CO_2 (g) + 3 H_2O (g) \]

4. Make all coefficients whole numbers by multiplying through by 2:
   \[ 2 C_4H_6 (g) + 11 O_2 (g) \rightarrow 8 CO_2 (g) + 6 H_2O (g) \]

5. Sum of the balanced coefficients:
   - \(2 + 11 + 8 + 6 = 27\)

Please enter 27 as your answer.
Transcribed Image Text:**Balancing Combustion Reactions** In this exercise, balance and complete the following combustion reaction. After balancing, enter the sum of the coefficients as your answer. If a coefficient is not explicitly listed (i.e., a "blank" coefficient), it is assigned a value of 1. ### Reaction: - **Tetracarbon Hexahydride (g) + Oxygen (g) —> ?** ### Instructions: 1. Identify the chemical formula for tetracarbon hexahydride: This is commonly known as butane, with the formula \( C_4H_6 \). 2. Write the unbalanced combustion reaction: \[ C_4H_6 (g) + O_2 (g) \rightarrow CO_2 (g) + H_2O (g) \] 3. Balance the equation: - Balance carbon atoms first: \[ C_4H_6 (g) + O_2 (g) \rightarrow 4 CO_2 (g) + H_2O (g) \] - Balance hydrogen atoms next: \[ C_4H_6 (g) + O_2 (g) \rightarrow 4 CO_2 (g) + 3 H_2O (g) \] - Finally, balance oxygen atoms: - Total O on right = \( 4 \times 2 + 3 \times 1 = 11 \) - Therefore, we balance by adjusting \( O_2 \): \[ C_4H_6 (g) + \frac{11}{2} O_2 (g) \rightarrow 4 CO_2 (g) + 3 H_2O (g) \] 4. Make all coefficients whole numbers by multiplying through by 2: \[ 2 C_4H_6 (g) + 11 O_2 (g) \rightarrow 8 CO_2 (g) + 6 H_2O (g) \] 5. Sum of the balanced coefficients: - \(2 + 11 + 8 + 6 = 27\) Please enter 27 as your answer.
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