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b. ~(x)(Fx~Gx) = (3x)(Fx Gx) (~E= 1)

b. ~(x)(Fx~Gx) = (3x)(Fx Gx) (~E= 1)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Problem b

3. Using just Q.N. and your propositional replacement rules, derive the following C.Q.N. equivalences. *a. ~(3x)(Fx*~Gx) = (x)(FxGx) b. ~(x) (Fx ~Gx) = (3x)(Fx Gx) *c. (3x)(Fx Gx) = (x)(Fx~Gx) (~0 = A) (~E= 1) (~1 = E)
Transcribed Image Text:3. Using just Q.N. and your propositional replacement rules, derive the following C.Q.N. equivalences. *a. ~(3x)(Fx*~Gx) = (x)(FxGx) b. ~(x) (Fx ~Gx) = (3x)(Fx Gx) *c. (3x)(Fx Gx) = (x)(Fx~Gx) (~0 = A) (~E= 1) (~1 = E)
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