b. THUN daw moitsen shnoo noz NaOH H₂O Br

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Predict-the-product. Draw the structure(s) of the major organic profuct(s) formed in the following reactions. Please indicate stereochemistry if appropriate. 

### Reaction Mechanism Transcription

**Title:** Aldol Reaction with Pyridinium Bromide

**Chemical Equation:**

Below is a chemical reaction involving a benzaldehyde derivative and a pyridinium bromide salt, under basic conditions provided by sodium hydroxide (NaOH) in the presence of water (H₂O). 

**Reactants:**
1. Benzaldehyde derivative with a methyl group at the para position.
2. Pyridinium bromide (having a sulfur group attached).

**Reagents:**
- NaOH (Sodium Hydroxide)
- H₂O (Water)

**Reaction Scheme:**
```
      O
      ||
C6H4-C-CH3 +  C5H4N-S-Br
                      |
                     NaOH, H2O
```
*Note:* The above scheme describes the initial reactants on the left, with the benzaldehyde derivative and pyridinium bromide reacting under basic conditions (NaOH) and water (H₂O).

**Explanation of Graph/Diagram:**
- **Left Reactant:** The left-side reactant is a benzaldehyde derivative featuring a benzene ring (C6H4) connected to an aldehyde group (C=O) with a methyl group (CH3) on the para position of the benzene ring.
- **Reacting Compound:** The reacting compound is a pyridinium bromide, containing a pyridine ring (C5H4N) with a sulfur group adjacent to the nitrogen, and bromide as a counter-ion.
- **Reagent and Conditions:** Sodium hydroxide (NaOH) is added to the mixture in the presence of water (H₂O).
  
Unfortunately, the product of the reaction is not displayed in the image. However, this setup typically illustrates an aldol condensation or related reaction, where the carbonyl compound undergoes a base-catalyzed addition forming a new product.

**Educational Context:**
This reaction could be part of a study on aldol condensation reactions, demonstrating how different substituents on the starting materials can affect the outcome and properties of the products formed under various conditions. The mechanism involves deprotonation, nucleophilic attack, and subsequent rearrangement to form the product.
Transcribed Image Text:### Reaction Mechanism Transcription **Title:** Aldol Reaction with Pyridinium Bromide **Chemical Equation:** Below is a chemical reaction involving a benzaldehyde derivative and a pyridinium bromide salt, under basic conditions provided by sodium hydroxide (NaOH) in the presence of water (H₂O). **Reactants:** 1. Benzaldehyde derivative with a methyl group at the para position. 2. Pyridinium bromide (having a sulfur group attached). **Reagents:** - NaOH (Sodium Hydroxide) - H₂O (Water) **Reaction Scheme:** ``` O || C6H4-C-CH3 + C5H4N-S-Br | NaOH, H2O ``` *Note:* The above scheme describes the initial reactants on the left, with the benzaldehyde derivative and pyridinium bromide reacting under basic conditions (NaOH) and water (H₂O). **Explanation of Graph/Diagram:** - **Left Reactant:** The left-side reactant is a benzaldehyde derivative featuring a benzene ring (C6H4) connected to an aldehyde group (C=O) with a methyl group (CH3) on the para position of the benzene ring. - **Reacting Compound:** The reacting compound is a pyridinium bromide, containing a pyridine ring (C5H4N) with a sulfur group adjacent to the nitrogen, and bromide as a counter-ion. - **Reagent and Conditions:** Sodium hydroxide (NaOH) is added to the mixture in the presence of water (H₂O). Unfortunately, the product of the reaction is not displayed in the image. However, this setup typically illustrates an aldol condensation or related reaction, where the carbonyl compound undergoes a base-catalyzed addition forming a new product. **Educational Context:** This reaction could be part of a study on aldol condensation reactions, demonstrating how different substituents on the starting materials can affect the outcome and properties of the products formed under various conditions. The mechanism involves deprotonation, nucleophilic attack, and subsequent rearrangement to form the product.
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