B. Table 2: Solving for the variance and standard deviation of the discrete random variable. Probability P(X) X• P(X) (X — и)2 (X — и)2 - Р(X) (X) Σ 2x• P(X) = Variance (o2) = Mean (u) = Standard Deviation (ơ) =

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Author:Sheldon Ross
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Chapter1: Combinatorial Analysis
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Probability

The number of pets at home was defined as :

Last Name Response
Rasales 2
Lasrera 2
Launto 0
Cantila 3
Kho 3
Magrina 3
Sugabo 3
Mirafelix 2
Dela Cruz 4
Monteurgen 0
Martinez 6
Luma-as 2
Meja 4
Malonzo 0
Magcalas 3
Palangdao 8
Sagcal 0
Salazar 4
Pineda 8
Mina 3

From the data given, discrete probability distribution as :

x Frequency f Px=fn x×Px
0 4 0.20 0.0000
2 4 0.20 0.4000
3 6 0.30 0.9000
4 3 0.15 0.6000
6 1 0.05 0.3000
8 2 0.10 0.8000
Total n=20 1 3

From the data given in the table, 

∑x×Px=3μ=3

Thus, the mean is 3

MINOR PERFORMANCE TASK
Students will ask 20 classmates and/or strand mates random question that will
require 1 quantitative discrete answer. They will then evaluate the answers and find its
corresponding probability. The students will solve and interpret the mean, variance and
standard deviation of the obtained data.
Survey Question:
How many peets do you have at home?
Response:
Last Name
1 Rasales
2 Ladrera
3 Launto
4 Can tila
5 kho
6 Magriña
7 Suoabo
8 Mira felix
9 Dela Cruz
10 Monteuirgen
Response (X)
2
2.
Response (X)
Last Name
11 Maytinez
12 Luma-as.
13 Meja
14 Malonzo
4.
3.
3.
3.
16 Palángdao
17 Sagcal
18 Salazar
19 Pineda
20 Mina
3.
3.
Transcribed Image Text:MINOR PERFORMANCE TASK Students will ask 20 classmates and/or strand mates random question that will require 1 quantitative discrete answer. They will then evaluate the answers and find its corresponding probability. The students will solve and interpret the mean, variance and standard deviation of the obtained data. Survey Question: How many peets do you have at home? Response: Last Name 1 Rasales 2 Ladrera 3 Launto 4 Can tila 5 kho 6 Magriña 7 Suoabo 8 Mira felix 9 Dela Cruz 10 Monteuirgen Response (X) 2 2. Response (X) Last Name 11 Maytinez 12 Luma-as. 13 Meja 14 Malonzo 4. 3. 3. 3. 16 Palángdao 17 Sagcal 18 Salazar 19 Pineda 20 Mina 3. 3.
B. Table 2: Solving for the variance and standard deviation of the discrete random
variable.
Probability
P(X)
X• P(X)
(X — и)2
(X — и)2 . Р(X)
(X)
Ex• P
X• P(X) =
Variance (o?) =
Mean (u) =
Standard Deviation (o) =
Transcribed Image Text:B. Table 2: Solving for the variance and standard deviation of the discrete random variable. Probability P(X) X• P(X) (X — и)2 (X — и)2 . Р(X) (X) Ex• P X• P(X) = Variance (o?) = Mean (u) = Standard Deviation (o) =
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