B. Table 2: Solving for the variance and standard deviation of the discrete random variable. Probability P(X) X• P(X) (X — и)2 (X — и)2 - Р(X) (X) Σ 2x• P(X) = Variance (o2) = Mean (u) = Standard Deviation (ơ) =
B. Table 2: Solving for the variance and standard deviation of the discrete random variable. Probability P(X) X• P(X) (X — и)2 (X — и)2 - Р(X) (X) Σ 2x• P(X) = Variance (o2) = Mean (u) = Standard Deviation (ơ) =
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Question
Probability
The number of pets at home was defined as :
Last Name | Response |
Rasales | 2 |
Lasrera | 2 |
Launto | 0 |
Cantila | 3 |
Kho | 3 |
Magrina | 3 |
Sugabo | 3 |
Mirafelix | 2 |
Dela Cruz | 4 |
Monteurgen | 0 |
Martinez | 6 |
Luma-as | 2 |
Meja | 4 |
Malonzo | 0 |
Magcalas | 3 |
Palangdao | 8 |
Sagcal | 0 |
Salazar | 4 |
Pineda | 8 |
Mina | 3 |
From the data given, discrete probability distribution as :
x | Frequency f | Px=fn | x×Px |
0 | 4 | 0.20 | 0.0000 |
2 | 4 | 0.20 | 0.4000 |
3 | 6 | 0.30 | 0.9000 |
4 | 3 | 0.15 | 0.6000 |
6 | 1 | 0.05 | 0.3000 |
8 | 2 | 0.10 | 0.8000 |
Total | n=20 | 1 | 3 |
From the data given in the table,
∑x×Px=3μ=3
Thus, the mean is 3
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