a)Given the probability distribution below, find the missing value, : -710.10151y690.226-30.0661190.083 b)Given the distribution below, what is EX? -180.2210.54160.01430.11580.12

a) Define the probability distribution p(x) for random variable x. The probability distribution p(x)…

Answered: a) Given the probability distribution…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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According to a health publication, 16.5% of persons under the age of 65 have no health insurance coverage. Suppose that four persons under the age of 65 are randomly selected. a. Determine the probability distribution for the number, X, who have no health insurance coverage. b. Determine and interpret the mean of X.
Let X = {Email, In Person, Instant Message, Text Message}; P(Email) = 0.06 P(In Person) = 0.55 P(Instant Message) = 0.24 P(Text Message) = 0.15 Is this model a probability distribution? A. Yes. B. No. C. Maybe.
Given N(23.4, 6.2), the probability that X is less than 23.4, is: 0.25 0.75 0.67 0.5
IV. Solve the problem. (don't forget to attached the solution) The Xiaomi brand releases three cellphones that are tested at random. a. Construct the probability distribution of the random variable X (number of defective cellphones). Let G represent non-defective cellphones and, Let F be the defective cellphones. b. Create a histogram representing the distribution
Use the geometric distribution to calculate the following probabilities. a.Find the probability that the first success occurs on the third trial when ?=0.3p=0.3. b.Find the probability that the first success occurs on the fifth trial when ?=0.3p=0.3. c.Find the probability that the first success occurs on the third trial or later when ?=0.3p=0.3. d.Find the probability that the first success occurs on or before the third trial ?=0.3p=0.3. e.Find the probability that the first success occurs on the second or third trial when ?=0.3p=0.3.
From the table, find the probability that the person is a: 1. Male from area IV 2. Female and not from area III or area V
Refer to this figure to answer number 8- 10. The table below show the probability distribution of number of face mask sold per day. 1 2 3 5 6. 7 8. 10 0.07 P(x) P/x) 0.16 0.07 0.1 0.09 0.1 0.07 0.08 0.1 0.17 0.56 1.4 1.96 5.76 11.56 0.16 0.40 0.16 0.14 0.3 0.36 0.5 0.42 0.56 0.9 1.7 X-U -4.6 -3.6 -2.6 -1.6 -0.6 0.4 2.4 3.4 4.4 (x-)A2 (x-u)A2 *P(x) 21.16 12.96 6.76 2.56 0.36 0.16 19.36 3.39 0.91 0.68 0.23 0.04 0.01 1.16 3.29 8. What is ExP(x) =? A. 5.6 B. 6.5 C.7 D. 8 9. What is a? = E[(x - 4) P(x)] A. 5.9 %3D В. 8.6 С. 10.25 D. 11.35 10. If the standard deviation of the variance of problem number 9 is 3.20156, then how do we get the value of standard deviation given the value of variance? A. Vo? B. Va C. uP(x) D. o ololo-
Complete the following probability distribution table: X 6 34 35 81 88 PXXX) 0.2 0.26 0.26 0.14 Submit Question WE 4 R 5
Given the probability distribution below, find the missing value, : -71 0.121 39 y 85 0.070 -38 0.153 124 0.017
Find the indicated probability. The age distribution of students at a community college is given below. Number of students Age (years) (f) Under 21 411 21-25 413 26-30 203 31-35 58 Over 35 24 1109 A student from the community college is selected at random. Find the probability that the student is at least 31. Round your answer to three decimal places. O 0.926 82 O 0.052 O 0.074 ASUS 近

Homework Housework Outside Employment Recreation Other Total Male 29 15 20 23 96 Female 18 17 26 39 4 104 Total 47 32 46 62 13 200
The amount of coffee that people drink per day is normally distributed with a mean of 16 ounces and a standard deviation of 5.5 ounces. 35 randomly selected people are surveyed. Round all answers to 4 decimal places where possible. a. What is the distribution of X? X - N b. What is the distribution of ? T - N( c. What is the probability that one randomly selected person drinks between 15.7 and 16.1 ounces of coffee per day?

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-71	0.101
51	y
69	0.226
-3	0.066
119	0.083


-18	0.22
1	0.54
16	0.01
43	0.11
58	0.12

a) Given the probability distribution below, find the missing value, : -71 0.101 51 y 69 0.226 -3 0.066 119 0.083 b) Given the distribution below, what is EX? -18 0.22 1 0.54 16 0.01 43 0.11 58 0.12