B. In a series of tests to determine the parameters of an eight pole, three-phase 3300 V, 50 Hz,500 kW induction motor, the test results were obtained. The stator winding resistance wasseparately determined to be equal to 0.3 2, and the mechanical losses are equal to 10 kW.Table 1 Test results for wound-rotor induction machineTestVoltageCurrentPowerNo-load test3300 V4.711 A10.01 kWLocked-rotor test336.6 V86.56 A12.24 kW(i)Calculate the synchronous speed of the motor.(ii)If the slip at rated load is 0.02, calculate the full-load speed of the motor.Calculate the shaft torque at rated load.(iii)(iv)Using the test results in table 1, calculate the parameters of the approximateequivalent circuit.(v)If the motor is started direct-on-line, calculate the starting current, and the developedstarting torque. The magnetizing branch can be neglected in this analysis.(vi)(vii)What is the disadvantage of starting big motors using direct-on-line starting?Calculate the external resistors that should be connected in the rotor circuit to achievemaximum starting torque.(viii)Calculate the starting current and the starting torque when the resistors calculated inpart (vii) are in the rotor circuit.(ix)By what factor does the addition of the external resistors increase the starting torque?

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B. In a series of tests to determine the parameters of an eight pole, three-phase 3300 V, 50 Hz, 500 kW induction motor, the test results were obtained. The stator winding resistance was separately determined to be equal to 0.3 2, and the mechanical losses are equal to 10 kW. Table 1 Test results for wound-rotor induction machine Test Voltage Current Power No-load test 3300 V 4.711 A 10.01 kW Locked-rotor test 336.6 V 86.56 A 12.24 kW (i) Calculate the synchronous speed of the motor. (ii) If the slip at rated load is 0.02, calculate the full-load speed of the motor. Calculate the shaft torque at rated load. (iii)

B. In a series of tests to determine the parameters of an eight pole, three-phase 3300 V, 50 Hz, 500 kW induction motor, the test results were obtained. The stator winding resistance was separately determined to be equal to 0.3 2, and the mechanical losses are equal to 10 kW. Table 1 Test results for wound-rotor induction machine Test Voltage Current Power No-load test 3300 V 4.711 A 10.01 kW Locked-rotor test 336.6 V 86.56 A 12.24 kW (i) Calculate the synchronous speed of the motor. (ii) If the slip at rated load is 0.02, calculate the full-load speed of the motor. Calculate the shaft torque at rated load. (iii)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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A 240 V, 60 Hz, Delta connected, 870 r.p.m., Eight poles, Three-Phase Induction Motor has the following per phase parameters: R1 = 0.07, R2 = 0.05, X1 = X2 = 0.2, Xm = 6.5, Draw the approximate equivalent circuit and determine the following: I. Starting Torque Maximum Torque II. I. Rated Torque IV. Stator Current V. Power Factor VI. Input Power VII. Rotor Current VIII. Magnetizing Current IX. Stator copper loss Х. Rotor copper loss