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B. Given e" (1+ e*)-$dx. Let u = (5). Then, du = Now, we can write ----- ---- the integral as / -(6). Evaluating the integral gives the answer (in terms of x) a. e* 3 f. udu g. (1+e")³ +C b. (1+ e*)} +C 2 C. udu h. e"dx d. (1+e*)-} i. ue" dx 1 e. 1+ e" j. -(1+e*)-{e'dr

B. Given e" (1+ e*)-$dx. Let u = (5). Then, du = Now, we can write ----- ---- the integral as / -(6). Evaluating the integral gives the answer (in terms of x) a. e* 3 f. udu g. (1+e")³ +C b. (1+ e*)} +C 2 C. udu h. e"dx d. (1+e*)-} i. ue" dx 1 e. 1+ e" j. -(1+e*)-{e'dr

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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B. ( Please answer all )
/ e*(1+e*)¯³dx. Let u = the integral as / B. Given (5). Then, du = Now, we can write -(6). Evaluating the integral gives the answer (in terms of x) a. et f. ušdu b. (1+e*)} + C g. (1+e*)} +C с. иdu h. e*dx d. (1+e*)- i. ue" dx 1 e. 1+ eª j. -(1+ e*)-š&dr
Transcribed Image Text:/ e*(1+e*)¯³dx. Let u = the integral as / B. Given (5). Then, du = Now, we can write -(6). Evaluating the integral gives the answer (in terms of x) a. et f. ušdu b. (1+e*)} + C g. (1+e*)} +C с. иdu h. e*dx d. (1+e*)- i. ue" dx 1 e. 1+ eª j. -(1+ e*)-š&dr
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