Evaluate. 15! 13! The solution is
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Question
![Evaluate.
\[
\frac{15!}{13!}
\]
The solution is [ ].
**Explanation:**
To solve \( \frac{15!}{13!} \), you can simplify the expression by canceling out the common terms in the factorials:
1. \( 15! = 15 \times 14 \times 13! \)
2. Substitute into the expression: \( \frac{15 \times 14 \times 13!}{13!} \)
3. Cancel out \( 13! \) from the numerator and denominator.
This leaves you with \( 15 \times 14 \).
Calculating \( 15 \times 14 \):
\[ 15 \times 14 = 210 \]
Therefore, the solution is 210.
**Fill in the solution box with:** 210](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F35ad263b-c31f-4196-aa81-a0a5a787610e%2F6103724f-d6ad-4e9a-8c3f-f9dbd75e43b5%2F1d34sgl_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Evaluate.
\[
\frac{15!}{13!}
\]
The solution is [ ].
**Explanation:**
To solve \( \frac{15!}{13!} \), you can simplify the expression by canceling out the common terms in the factorials:
1. \( 15! = 15 \times 14 \times 13! \)
2. Substitute into the expression: \( \frac{15 \times 14 \times 13!}{13!} \)
3. Cancel out \( 13! \) from the numerator and denominator.
This leaves you with \( 15 \times 14 \).
Calculating \( 15 \times 14 \):
\[ 15 \times 14 = 210 \]
Therefore, the solution is 210.
**Fill in the solution box with:** 210
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