B. From what maximum height can a 70 kg person jump without breaking the lower leg bone on either leg? Ignore air resistance and assume the body of the person moves a distance of 5 cm form the standing to the seated position in breaking the fall. Assume the strength (force per area) of bone is 170 x 10°N/m² , and its smallest cross-sectional area is 2.5 x 10-4m² .
B. From what maximum height can a 70 kg person jump without breaking the lower leg bone on either leg? Ignore air resistance and assume the body of the person moves a distance of 5 cm form the standing to the seated position in breaking the fall. Assume the strength (force per area) of bone is 170 x 10°N/m² , and its smallest cross-sectional area is 2.5 x 10-4m² .
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![3. From what maximum height can a 70 kg person jump without breaking the lower leg bone on either leg? Ignore air resistance and assume the body of the person moves a distance of 5 cm from the standing to the seated position in breaking the fall. Assume the strength (force per area) of bone is \(170 \times 10^6 \, \text{N/m}^2\), and its smallest cross-sectional area is \(2.5 \times 10^{-4} \, \text{m}^2\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F53b7e047-7241-484e-a94a-313a17cd161e%2Fb0d491b0-3055-426f-8e4d-2707ee0728f9%2Fn3u6jpp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3. From what maximum height can a 70 kg person jump without breaking the lower leg bone on either leg? Ignore air resistance and assume the body of the person moves a distance of 5 cm from the standing to the seated position in breaking the fall. Assume the strength (force per area) of bone is \(170 \times 10^6 \, \text{N/m}^2\), and its smallest cross-sectional area is \(2.5 \times 10^{-4} \, \text{m}^2\).
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