For each of the following pairs, pick which one has the better leaving group. **Problem: Evaluating Leaving Groups****Instruction:** For each of the following pairs, pick which one has the better leaving group by circling the correct answer. *(Hint: Look at the pKa values of the conjugate acid of the leaving group.)***a)** Cyclohexane with an attached \( \text{NH}_3^+ \) group vs. cyclohexane with an attached ester group \( \text{O=C-OCH}_3 \).**b)** Cyclohexane with an attached \( \text{OH}_2^+ \) group vs. cyclohexane with an attached \( \text{Cl} \) group.**c)** Cyclohexane with an attached \( \text{F} \) group vs. cyclohexane with an attached \( \text{CN} \) group.**d)** Cyclohexane with an attached \( \text{OCH}_3 \) group vs. cyclohexane with an attached \( \text{CH}_3 \) group.**Explanation:** Consider the stability of the leaving group based on the pKa values of its conjugate acid. The lower the pKa value, the stronger the acid, and the better the leaving group.

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b. For each of the following pairs, pick which one has the better leaving group by circling the correct answer. (HINT: look at the pK, values of the conjugate acid of the L.G.) b) COH2 NH3 or .CI or с) .F CN d) LOCH3 CH3 or or

b. For each of the following pairs, pick which one has the better leaving group by circling the correct answer. (HINT: look at the pK, values of the conjugate acid of the L.G.) b) COH2 NH3 or .CI or с) .F CN d) LOCH3 CH3 or or

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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In case of dihalide like problem 8.54 c. 1. my think is like this. at the first E2 reaction, the hydrogen on cyclohexyl will be participate because its carbon is more substituted. then second E2 reaction, there are no more hydrogen on left carbon. so hydrogen on right carbon will be partcipate. as a result, the product is double bond not triple bond. Why is this wrong and only form triple bond? 2. Is it impossible to make Sn2 reaction that NH2- is working as nucleophile?
Label the nucleophile and leaving group, and draw the product (includingstereochemistry) of the following SN2 reaction.
Is this a good or a bad nucleophile?
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Complete these SN2 reactions, showing the configuration of each product.
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