b. Explain your observations in Step 4. (In which direction did Reaction 5 shift when heated? What must have happened to the value of K., in the hot solution? What does this tell you about the sign of AH in Reaction 5?) c. Explain why the PbCl₂ dissolved when water was added in Step 5. (What was the effect of the added water on [Pb²+] and [CI]? In what direction would such a change drive Reaction 5?) HMV(aq) H(aq) + MV¯ (aq) yellow violet PbCl₂(s) is reaction takes the form Pb2+ (aq) + 2 Cl(aq) K. = [Pb²+] x [CI] = Ksp (5) (6)
b. Explain your observations in Step 4. (In which direction did Reaction 5 shift when heated? What must have happened to the value of K., in the hot solution? What does this tell you about the sign of AH in Reaction 5?) c. Explain why the PbCl₂ dissolved when water was added in Step 5. (What was the effect of the added water on [Pb²+] and [CI]? In what direction would such a change drive Reaction 5?) HMV(aq) H(aq) + MV¯ (aq) yellow violet PbCl₂(s) is reaction takes the form Pb2+ (aq) + 2 Cl(aq) K. = [Pb²+] x [CI] = Ksp (5) (6)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can I get help understanding question a, b, and c?
![b. Explain your observations in Step 4. (In which direction did Reaction 5 shift when heated? What
must have happened to the value of K., in the hot solution? What does this tell you about the sign of
AH in Reaction 5?)
c. Explain why the PbCl₂ dissolved when water was added in Step 5. (What was the effect of the added
water on [Pb²+] and [CI]? In what direction would such a change drive Reaction 5?)
HMV (aq) H*(aq) + MV (aq)
yellow
violet
PbCl₂(s)
or this reaction takes the form
Pb2+ (aq) + 2 Cl(aq)
K = [Pb²+] x [CI] = Ksp
(5)
(6)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1a2e06cd-89b1-4949-854a-ccc1923a28fc%2F8bef6e42-f0a5-4b54-a402-198f2b53636f%2Fdpnkip9_processed.png&w=3840&q=75)
Transcribed Image Text:b. Explain your observations in Step 4. (In which direction did Reaction 5 shift when heated? What
must have happened to the value of K., in the hot solution? What does this tell you about the sign of
AH in Reaction 5?)
c. Explain why the PbCl₂ dissolved when water was added in Step 5. (What was the effect of the added
water on [Pb²+] and [CI]? In what direction would such a change drive Reaction 5?)
HMV (aq) H*(aq) + MV (aq)
yellow
violet
PbCl₂(s)
or this reaction takes the form
Pb2+ (aq) + 2 Cl(aq)
K = [Pb²+] x [CI] = Ksp
(5)
(6)
![B. Solubility Equilibrium; Finding a Value for Ksp
2+
2. Vol. 0.30 M Pb(NO3)2 = 5.0 mL moles Pb²+ = [M× V(stock)] = 1.5 × 10-³ moles
Observations:
3. Vol. 0.30 M HCl used
4
percipitate dissolved
4. Observations: in hot water
Total volume of solution
5. Volume of H₂O added to dissolve PbCl₂
18
mL; moles Cl added
in cold water
mL
.0012 moles
percipitaté formselmoo.c
19
mL
a. Explain why PbCl₂ did not precipitate immediately on addition of HCl. (What condition must be met
by [Pb²+] and [CI] if PbCl₂ is to form?)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1a2e06cd-89b1-4949-854a-ccc1923a28fc%2F8bef6e42-f0a5-4b54-a402-198f2b53636f%2Fr52l628.jpeg&w=3840&q=75)
Transcribed Image Text:B. Solubility Equilibrium; Finding a Value for Ksp
2+
2. Vol. 0.30 M Pb(NO3)2 = 5.0 mL moles Pb²+ = [M× V(stock)] = 1.5 × 10-³ moles
Observations:
3. Vol. 0.30 M HCl used
4
percipitate dissolved
4. Observations: in hot water
Total volume of solution
5. Volume of H₂O added to dissolve PbCl₂
18
mL; moles Cl added
in cold water
mL
.0012 moles
percipitaté formselmoo.c
19
mL
a. Explain why PbCl₂ did not precipitate immediately on addition of HCl. (What condition must be met
by [Pb²+] and [CI] if PbCl₂ is to form?)
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