Show full work equation **Problem Statement:**Determine the coefficient of friction, \(\mu\), if \(M_1 = 2\) kg, \(M_2 = 3\) kg, \(I = 0.045 \) kg·m\(^2\), \(a = 0.5\) m/s\(^2\), and \(R\) is 0.06 m. **Problem 1: Mass, Pulley, and Friction Dynamics**A mass \( M_1 \) is connected, as shown, by a light cord to a mass \( M_2 \), which slides on a horizontal surface. The pulley rotates about a frictionless axle and has a radius \( R \) and a moment of inertia \( I \). The cord does not slip on the pulley. If the coefficient of kinetic friction between \( M_2 \) and the horizontal surface is \( \mu_k \), and \( M_1 \) moves with acceleration \( a \),**Tasks:**a. Find an expression for the coefficient of kinetic friction in terms of the given parameters and \( g \) (acceleration due to gravity).**Diagram Explanation:**The diagram illustrates the setup of the problem. There is a pulley system where:- Mass \( M_2 \) is placed on a horizontal surface to the right of the pulley.- Mass \( M_1 \) is hanging vertically on the left of the pulley.- The cord connecting \( M_1 \) and \( M_2 \) passes over the pulley and does not slip. The system demonstrates basic principles of mechanics, where mass \( M_1 \) contributes to the tension in the cord, and mass \( M_2 \) experiences friction due to its motion across the horizontal surface. The friction, tension in the cord, and rotation of the pulley all influence the acceleration of the masses in the system.Visual learners may benefit from focusing on how the forces interact in this illustration, including the tension in the cord, frictional force on \( M_2 \), and gravitational force on \( M_1 \), giving insight into the dynamics of the system.

Solution: a. Let a be the acceleration of the system. Then according to Newton's second law of…

Answered: b. Determine if M₁ = 2-kg, M₂ = 3-kg, I…