b. Construct the confidence interval suitable for testing the claim in part (a). |<₁-1₂ | (Round to two decimal places as needed.)
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- 1) When we compute a 95% confidence interval (CI) using a sample meana. 95% of the time it will include the population mean b. we have an interval estimate of population meanc. 5% of the time it will not include the population mean d. we can't be absolutely sure population mean is in the CIe. all the above are correct 2) In R, what argument does the function: str( ) expect? a. name of an object b. proper punctuation c. xlim d. plot e. col=8 f. pch g. The function name h. none of the aboveThe hypotheses Ho pW = pm Ha pw ≠ pm were tested and had a p-value of .08, the correspondingconfidence interval…. a. will contain .08 b. will not contain .08 c. will contain 0 d. will not contain 0 e. will have 2 positive #sAssume that the sample is a simple random sample obtained from a normally distributed population of IQ scores of statistics professors. Use the table below to find the minimum sample size needed to be 95% confident that the sample standard deviation s is within 40% of sigma. Is this sample size practical? a. The minimum sample size needed is
- Ocean currents are important in studies of climate change, as well as ecology studies of dispersal of plankton. Drift bottles are used to study ocean currents in the Pacific near Hawaii, the Solomon Islands, New Guinea, and other islands. Let x represent the number of days to recovery of a drift bottle after release and y represent the distance from point of release to point of recovery in km/100. The following data are representative of one study using drift bottles to study ocean currents. x days y km/100 71 76 31 92 203 14.2 19.6 5.8 11.2 35.9 (a) Verify that Ex : 473, Ey = 86.7, Ex? 61,451, Ey = 2033.69, Exy = 10995.7, and r- 0.93868. %3D %3D %3D Σχ Ey Ex? Ey2 Exy (b) Use a 1% level of significance to test the claim p > 0. (Use 2 decimal places.) critical t Conclusion Reject the null hypothesis, there is sufficient evidence that p > 0. O Reject the null hypothesis, there is insufficient evidence that p > 0. O Fail to reject the null hypothesis, there is insufficient evidence that p…q29E- Answer to part D was - (0.0801, 0.1699)Calculate the margin of error and construct the confidence interval for the population mean using the Student's t-distribution (you may assume the population data is normally distributed). -Distribution Table a. x = 86.8, n = 68, s = 10.4, 99% confidence - Round to two decimal places if necessary k € <μ< SAMSUNG SUBMIT QUESTION SAVE PROGRESS SUBMIT AS
- Male BMI Female BMI H2 Given in the table are the BMI statistics for random samples of men and women. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. 44 44 27.2839 24.5463 7.155619 4.932995 a. Test the claim that males and females have the same mean body mass index (BMI). What are the null and alternative hypotheses? O A. Ho: H1 =H2 H1: Hy > H2 B. Ho: H1 # H2 H1: H1If n=17, ¯x=44, and s=8, find the MARGIN OF ERROR at a 98% confidence levelRecall: M.O.E. = t*⋅s√nGive your answer to two decimal places. I need help my homework3. The steps for used to solve a Central Limit Theorem problem are almost exactly the same as the steps used to solve which problem listed below? (Hint: the only difference is the z-score formula used) A. Forward Normal B. Reverse Normal C. Normal Approximation to the Binomial D. Confidence Interval E. None of these82 image for 1 question! fill in the blanks pleaseSuppose a new treatment for a certain disease is given to a sample of 190 patients. The treatment was successful for 152 of the patients. Assume that these patients are representative of the population of individuals who have this disease. Calculate a 98% confidence interval for the proportion successfully treated. (Round the answers to three decimal places.) ___ to ___SEE MORE QUESTIONS