B. By Simple Substitution 1. [(x³ – 5)° x²dx -

Q: Simplify. [(20)²]³ 8i Enter your answer in the box.

A:

Q: -8y-9(2y²)°(4y¬8)-2

A:

Q: Let, A = [ 1 2 x 3 −1 2 ] and B = [ x y 1 ]. If AB = [ 6 8 ], find x and y.

A: Let, A = [ 1 2 x3 −1 2 ] and B = [xy1]. If AB = [68], find x and y.

Q: Evaluate. (10x³+4x² - 7x+2) dx

A:

Q: S 2sin(4x +9)dx

A: Given query is to find the integral ∫ 2 sin(4x+9)dx.

Q: Find the 4** x³ dx А. + c 4 In 4 В. + c 4 In 4 С. + c 3 In 3 D. 24 2 In 2

A:

Q: If x ∗ y = 2x – 3y + 4xy, find the values of 5 ∗ 2 and 3 * 2/5.

A: The solution is as

Q: 4. Find x (x2 + 2x)° 40° (x2+ 12x)°

A: The figure of the circle is given by To evaluate : The value of x

Q: 3.) Simplify (0.75x + 2y) - (0.3x – 0.6y)

A:

Q: .2 y = 4 - x² and x +y = 2.

A:

Q: Q. z =2+5i

A: Given complex number

Q: 5л — 2 dx x2 +1 10.)

A:

Q: (1 + 1)e dr 5.

A:

Q: d {(1+x – x²)°} da

A: Since you have asked multiple questions in single request,  So we will be answering only first…

Q: The value of   x –  x(xx) when x is -2 a. -1 1/2 b. – 2 ¼ c. -10 d. – 1 ¾

A:

Q: 2 x -dx 6. Jo 1-x

A:

Q: Exc. Eind. Lim (x-1) y3

A: Solution:

Q: x- dx = %3D

A: Given:

Q: tind y 3 O y=(++ y =9tan 4 ® y= x (2x+1) (4) %3D 1-VX

A:

Q: Q.2 a. Find the Domain for y- /4 -x +

A:

Q: 1. Find mzHKJ 239 (5х — 1)° (9x +2)° H. K MZHKJ =

A:

Q: (3x)° (2х+20)°

A:

Q: b. 3+V5-x 3I

A:

Q: 1 4x +3 dr

A:

Q: lim. J25x+2sh+6 50 25 x+650 w

A: Given,          limh→025x+25h+650-25x+650h

Q: y = x² + x y = x + 5 2

A: y=x2+x y=x+5   a2-b2=(a-b)(a+b)