b. At the 0.05 level of significance, using the p-value approach to hypothesis testing, is there evidence that the population mean waiting time to check out is less than 10.88 minutes? What is the p-value for this test? (Round to four decimal places as needed.)

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Find the p-value (Round to four decimal places as needed)

The waiting time to check out of a supermarket has had a population mean of 10.88 minutes. Recently, in an effort to reduce the waiting time, the supermarket has experimented with a system in which there is a single waiting line with multiple checkout servers. A sample of 50
customers was selected, and their mean waiting time to check out was 10.25 minutes with a sample standard deviation of 5.3 minutes. Complete parts (a) through (d).
Click here to view page 1 of the critical values for the t Distribution.
Click here to view page 2 of the critical values for the t Distribution.
a. At the 0.05 level of significance, using the critical value approach to hypothesis testing, is there evidence that the population mean waiting time to check out is less than 10.88 minutes?
What are the null and alternative hypotheses for this test?
O A. Ho: μ> 10.88
Η: με 10.88
D. Ho: μ² 10.88
Hy: με 10.88
What is the test statistic for this test?
-0.8405 (Round to four decimal places as needed.)
What is the critical value for this test?
-1.6766 (Round to four decimal places as needed.)
What is the conclusion for this test?
OB. Ho: μ< 10.25
Η: με 10.25
C
O E. Ho: p≤ 10.25
H₁: μ> 10.25
OC. Ho: μ≤ 10.88
H₁:μ> 10.88
OF. Ho: μz 10.25
Hy: μ<10.25
Since the test statistic is greater than the critical value, do not reject Ho. There is insufficient evidence to conclude that the population mean waiting time to check out is less than 10.88 minutes.
b. At the 0.05 level of significance, using the p-value approach to hypothesis testing, is there evidence that the population mean waiting time to check out less than 10.88 minutes?
What is the p-value for this test?
(Round to four decimal places as needed.)
Transcribed Image Text:The waiting time to check out of a supermarket has had a population mean of 10.88 minutes. Recently, in an effort to reduce the waiting time, the supermarket has experimented with a system in which there is a single waiting line with multiple checkout servers. A sample of 50 customers was selected, and their mean waiting time to check out was 10.25 minutes with a sample standard deviation of 5.3 minutes. Complete parts (a) through (d). Click here to view page 1 of the critical values for the t Distribution. Click here to view page 2 of the critical values for the t Distribution. a. At the 0.05 level of significance, using the critical value approach to hypothesis testing, is there evidence that the population mean waiting time to check out is less than 10.88 minutes? What are the null and alternative hypotheses for this test? O A. Ho: μ> 10.88 Η: με 10.88 D. Ho: μ² 10.88 Hy: με 10.88 What is the test statistic for this test? -0.8405 (Round to four decimal places as needed.) What is the critical value for this test? -1.6766 (Round to four decimal places as needed.) What is the conclusion for this test? OB. Ho: μ< 10.25 Η: με 10.25 C O E. Ho: p≤ 10.25 H₁: μ> 10.25 OC. Ho: μ≤ 10.88 H₁:μ> 10.88 OF. Ho: μz 10.25 Hy: μ<10.25 Since the test statistic is greater than the critical value, do not reject Ho. There is insufficient evidence to conclude that the population mean waiting time to check out is less than 10.88 minutes. b. At the 0.05 level of significance, using the p-value approach to hypothesis testing, is there evidence that the population mean waiting time to check out less than 10.88 minutes? What is the p-value for this test? (Round to four decimal places as needed.)
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