B. A 10-kVA, 2300/230-V transformer is to betested to determine its excitation branchcomponents, its series impedances and itsvoltage regulation. The following test datahave been taken from the primary side of thetransforme:.Open- circuit testVoc = 2300 VIoc = 0.20 A%3|Poc = 40 WThe data have been taken by using theconnections of open-circuit test and short-circuittest:a) Calculateregulation at 0.8 lagging power factorand 0.8 leading power factorthefull-loadvoltageb) What is the efficiency of thetransformer at full load with a powerfactor of 0.8 lagging?

10KVA voltage 2300/230 V Open circuit test parameters given Voltage regulation of 0.8 lagging power…

B. A 10-kVA, 2300/230-V transformer is to be tested to determine its excitation branch components, its series impedances and its voltage regulation. The following test data have been taken from the primary side of the transforme:. Open- circuit test Voc = 2300 V Ioc = 0.20 A Poc = 40 W The data have been taken by using the connections of open-circuit test and short-circuit test: a) Calculate regulation at 0.8 lagging power factor and 0.8 leading power factor the full-load voltage b) What is the efficiency of the transformer at full load with a power

B. A 10-kVA, 2300/230-V transformer is to be tested to determine its excitation branch components, its series impedances and its voltage regulation. The following test data have been taken from the primary side of the transforme:. Open- circuit test Voc = 2300 V Ioc = 0.20 A Poc = 40 W The data have been taken by using the connections of open-circuit test and short-circuit test: a) Calculate regulation at 0.8 lagging power factor and 0.8 leading power factor the full-load voltage b) What is the efficiency of the transformer at full load with a power

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

Find the elements of the equivalent circuit relative to the secondary of a single-phase transformer. The no-load voltages in the primary and secondary circuits are 200,400 volts, respectively, at a frequency of 50 Hz The primary no-load current at voltage 200 equals 0.7 amps and pulp losses equal to 70 watts Primary resistance and reactance 3.2 , 1.25 In order, the reactance of the resistance and the coil 0.6 , 0.7 Then draw the equivalent circle, explaining the values
formula for determining the power of a single-phase transformer
13)This MCQ QUESTION FROM BASIC POWER ELECTRICAL ENGINEERING course.
What are the objectives of conducting an open circuit test on single phase transformer?
4. 100 kVA, 6800-240 V, 50 Hz single phase step down transformer has the following parameters: RLs=0.0082 RHs=2.62 Rfe-HS=50002 XLs=0.015N XHs=5.2N Xm.Hs=88002 Transformer is delivering 80% of rated load at rated voltage and 0.95 lagging power factor. Determine the following: a) The equivalent impedance of the transformer referred to primary. b) Input impedance of the combined transformer and load. c) Actual input voltage at HV side. d) Input impedance if load is disconnected. e) Exciting current at no load.
Find the elements of the equivalent circuit attributed to the secondary of a single-phase transformer. The no-load voltages in the primary and secondary circuit are 200 volts and 400 volts, respectively, with a frequency of 50 Hz. The primary no-load current at the voltage of 200 volts is 0.7 amperes and the loss of the core is equal to 70 watts. The resistance and reactance of the primary are 3.2 ohms and 1.25 ohms, respectively. The resistance and reactance of the secondary are 0.6 ohm and 0.07 ohm, respectively. Draw the equivalent circle, showing the values of its elements.
A 36/240 V phase transformer, belonging to a phase measured from the no-load (idle) run and short-circuit test. values are given in the table below. High voltage by applying rated voltage to the low voltage winding (The winding ends were left unloaded and the results of the no-load test results were obtained. By applying nominal current to the high voltage windings, the low voltage windings were short-circuited, and the results of the short circuit test were obtained. In direct current test 1 V direct voltage is applied to the low voltage winding, and the transformer draws 500 A direct current. All equivalent Calculate the circuit elements as moved to the low voltage side. Idle run test: Voltage : 36V Power : 68W Current : 2,8A Short circuit test: Voltage : 15V Power : 325W Current : 42,2A
A 3.5 kV / 120V, 50 Hz, single phase transformer is to have an approximate e.m.f per turn of 33V and operate with a maximum flux density of 1.35T. Determine, (a) The number of primary and secondary turns. (b) The cross sectional area of the core.
What is transformer in electrical engineering?
What's The procedure of open circuit test on single phase transformer?
When rated voltage at rated frequency is applied to a single phase transformer, the hysteresis loss is 420W and eddy current loss is 150W, respectively. Solve for the new core loss if the voltage is increased by 10% and frequency is decreased by 5%.
5. Write down the equations of a single phase transformer at no-load mode. Give the names of the resistances, reactance, e.m.f.'s, currents and voltages.