A method for determining the equivalent network of a nonideal transformer consists of two tests: the open-circuit test and the short-circuit test. The open-circuit test, shown in figure (a), is usually done by applying rated voltage to the primary side of the transformer while leaving the secondary side open.The current into the primary side is measured, as is the power dissipated. The short-circuit test, shown in figure (b), is performed by increasing the primary voltage until rated current is going into the transformer while the secondary side is short-circuited. The current into the transformer, the applied voltage, and the power dissipated are measured.The equivalent circuit of a transformer is shown in figure (c), where rw and Lw represent the winding resistance and inductance, respectively, and rc and Lc represent the losses in the core of the transformer and the inductance of the core. The ideal transformer is also included in the model. With the open-circuit test, we may assume that Ĩprimary = Ĩsecondary = 0. Then all the current that is measured is directed through the parallel combination of rc and Lc. We also assume that ∣ rc ∣∣ jωLc ∣ is much greater than rw + jωLw. Using these assumptions and the open-circuit test data, we can find the resistance rc and the inductance Lc. In the short-circuit test, we assume that V˜�~ secondary is zero, so that the voltage on the primary side of the ideal transformer is also zero, causing no current through the rc ∣∣ Lc parallel combination. Using this assumption with the short-circuit test data, we are able to find the resistance rw and inductance Lw. The following test data was measured by the meters indicated in figures (a) and (b): open-circuit test: V˜ = 4600 V rms, I˜ = 0.7 A rms, and P = 200 W and short-circuit test: V˜ = 5.2 V rms, and P = 50 W.The transformer is rated at 460 kVA transformer and tests are performed at 60 Hz. Use the data to determine the equivalent network of the nonideal transformer.With the open-circuit test data, we can find the resistance and the inductance:rc = _________ kΩ.Lc = __________ H.With the short-circuit test data, we are able to find the resistance and inductance:rw = ___________ Ω.Lw = _________ H. Lwm'w=Lw=W(a)Le(b)Iprimary(c)eleellreeeeleC-O+IsecondarysecondaryWith the open-circuit test data, we can find the resistance and the inductance:rc=ΚΩ.H.4c=With the short-circuit test data, we are able to find the resistance and inductance:Ω.H. A method for determining the equivalent network of a nonideal transformer consists of two tests: the open-circuit test and the short-circuit test. The open-circuit test, shown in figure (a), is usually done by applying rated voltage to the primary side of the transformerwhile leaving the secondary side open.The current into the primary side is measured, as is the power dissipated. The short-circuit test, shown in figure (b), is performed byincreasing the primary voltage until rated current is going into the transformer while the secondary side is short-circuited. The currentinto the transformer, the applied voltage, and the power dissipated are measured.The equivalent circuit of a transformer is shown in figure (c), where and Lw represent the winding resistance and inductance,respectively, and rand Lc represent the losses in the core of the transformer and the inductance of the core. The ideal transformer isalso included in the model. With the open-circuit test, we may assume that primary secondary = 0. Then all the current that ismeasured is directed through the parallel combination of rc and Lc. We also assume that I c II WLcI is much greater than rw+JwLwUsing these assumptions and the open-circuit test data, we can find the resistance and the inductance Lc. In the short-circuit test,we assume that secondary is zero, so that the voltage on the primary side of the ideal transformer is also zero, causing no currentthrough the rell Lc parallel combination. Using this assumption with the short-circuit test data, we are able to find the resistance wand inductance Lw. The following test data was measured by the meters indicated in figures (a) and (b): open-circuit test: V = 4600 Vrms, I = 0.7 A rms, and P = 200 W and short-circuit test: V = 5.2 V rms, and P= 50 W.The transformer is rated at 460 KVA transformer and tests are performed at 60 Hz. Use the data to determine the equivalent networkof the nonideal transformer.

Given data Open circuit test; V=4600 V rms, I=0.7 A rms and P=200 W Short circuit test; V=5.2 V and…

A method for determining the equivalent network of a nonideal transformer consists of two tests: the open-circuit test and the short-circuit test. The open-circuit test, shown in figure (a), is usually done by applying rated voltage to the primary side of the transformer while leaving the secondary side open. The current into the primary side is measured, as is the power dissipated. The short-circuit test, shown in figure (b), is performed by increasing the primary voltage until rated current is going into the transformer while the secondary side is short-circuited. The current into the transformer, the applied voltage, and the power dissipated are measured. The equivalent circuit of a transformer is shown in figure (c), where rw and Lw represent the winding resistance and inductance, respectively, and rc and Lc represent the losses in the core of the transformer and the inductance of the core. The ideal transformer is also included in the model. With the open-circuit test, we may assume that Ĩprimary = Ĩsecondary = 0. Then all the current that is measured is directed through the parallel combination of rc and Lc. We also assume that ∣ rc ∣∣ jωLc ∣ is much greater than rw + jωLw. Using these assumptions and the open-circuit test data, we can find the resistance rc and the inductance Lc. In the short-circuit test, we assume that V˜�~ secondary is zero, so that the voltage on the primary side of the ideal transformer is also zero, causing no current through the rc ∣∣ Lc parallel combination. Using this assumption with the short-circuit test data, we are able to find the resistance rw and inductance Lw. The following test data was measured by the meters indicated in figures (a) and (b): open-circuit test: V˜ = 4600 V rms, I˜ = 0.7 A rms, and P = 200 W and short-circuit test: V˜ = 5.2 V rms, and P = 50 W. The transformer is rated at 460 kVA transformer and tests are performed at 60 Hz. Use the data to determine the equivalent network of the nonideal transformer. With the open-circuit test data, we can find the resistance and the inductance: rc = _________ kΩ. Lc = __________ H. With the short-circuit test data, we are able to find the resistance and inductance: rw = ___________ Ω. Lw = _________ H.