B. 2x³ +2y-3y² = 13x Steps 1. Take the derivative of both sides with respect to x. 2. Since the left side equation is a sum and difference of three terms, apply the Sum and Difference rule of differentiation by distributing the derivatives to them. 3. Perform the differentiation process. Use the Constant multiple rule of differentiation on the first and last term, then use the Chain rule on the second and third term (keep in mind that whenever you are taking the derivative of the variable y the answer is). 4. Use algebraic manipulation to isolate on one side of the equation solely and the rest to the other side. Solution dl d[] dx dx d(_)_ d(_)_d(_)_ d( dx dx dx dx (x) + (-)-(-) =() (Show your algebraic manipulation/solution here)
B. 2x³ +2y-3y² = 13x Steps 1. Take the derivative of both sides with respect to x. 2. Since the left side equation is a sum and difference of three terms, apply the Sum and Difference rule of differentiation by distributing the derivatives to them. 3. Perform the differentiation process. Use the Constant multiple rule of differentiation on the first and last term, then use the Chain rule on the second and third term (keep in mind that whenever you are taking the derivative of the variable y the answer is). 4. Use algebraic manipulation to isolate on one side of the equation solely and the rest to the other side. Solution dl d[] dx dx d(_)_ d(_)_d(_)_ d( dx dx dx dx (x) + (-)-(-) =() (Show your algebraic manipulation/solution here)
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
P2
![B. 2x +2y-3y² = 13x
Steps
1. Take the derivative of both sides
with respect to x.
2. Since the left side equation is a
sum and difference of three
terms, apply the Sum and
Difference rule of differentiation
by distributing the derivatives to
them.
3. Perform the differentiation
process. Use the Constant
multiple rule of differentiation on
the first and last term, then use
the Chain rule on the second
and third term (keep in mind that
whenever you are taking the
derivative of the variable y the
answer is
dx
4. Use algebraic manipulation to
isolate on one side of the
equation solely and the rest to
the other side.
5. Final answer
Solution
d[]
dx
dx
dd()_d__d(_))
+
dx
d
dx
(x) + (-x)(₁+x)=()
dx
dx
(Show your algebraic
manipulation/solution here)
dy
13-6x²
=
dx 2 - бу](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdc159504-9343-4a0c-9fca-456418f39780%2Fb014d796-368a-4372-92fb-035d03fbec09%2F8nwn17_processed.jpeg&w=3840&q=75)
Transcribed Image Text:B. 2x +2y-3y² = 13x
Steps
1. Take the derivative of both sides
with respect to x.
2. Since the left side equation is a
sum and difference of three
terms, apply the Sum and
Difference rule of differentiation
by distributing the derivatives to
them.
3. Perform the differentiation
process. Use the Constant
multiple rule of differentiation on
the first and last term, then use
the Chain rule on the second
and third term (keep in mind that
whenever you are taking the
derivative of the variable y the
answer is
dx
4. Use algebraic manipulation to
isolate on one side of the
equation solely and the rest to
the other side.
5. Final answer
Solution
d[]
dx
dx
dd()_d__d(_))
+
dx
d
dx
(x) + (-x)(₁+x)=()
dx
dx
(Show your algebraic
manipulation/solution here)
dy
13-6x²
=
dx 2 - бу
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