B velocity profile BC -1 at y=0 (n =0) ૧=૦ (૫=૦) → at y=s (n=1) y ? = (૫*) using BC 2 BC1 ve = svn/sy 0= BC0/0/0 y = f the s =0 Vx=0 vxve JVn бу a. sim 9, s. Karmen x = ve = 0 • Ve= ao sin I & 28 90 = ve velocity profil - ao a los 9, 8 at ao Pin an no slip condit ( free stream velicing, (zero shear stops at edge of boundary layer) y = 8 V₂= V₂ sin a ₁8 = π Integral solution FIN 9₁ ماد = T 28

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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TRANSCRIBE THE FOLLOWING TEXT IN DIGITAL FORMAT

BC
velocity profile
૪૬૦ (૫=૦)
at y=s (14)
(n +)
at y = 8 (1³²)
{ (n×)
at
Ⓒat
BC (1)
using 800 / 13
BL 2
y = f
ve =
avrlay
0=
Vx=0
v=v2
JVn
бу
=0
a. sim 9, s.
dx = ve
= 0
• V₂ = ao sin IX
28
90 = ve
at
ao a los 9, 8
au Pin ain
no slip condit
( free stream veliking,
(zero shear stres at
edge of boundary
layer)
y = 8
Vx= ve si
a₁8 = I
FIN
velocity profil
put in Von Karmen integral solution.
9₁
ماد
EN F/S
=
Transcribed Image Text:BC velocity profile ૪૬૦ (૫=૦) at y=s (14) (n +) at y = 8 (1³²) { (n×) at Ⓒat BC (1) using 800 / 13 BL 2 y = f ve = avrlay 0= Vx=0 v=v2 JVn бу =0 a. sim 9, s. dx = ve = 0 • V₂ = ao sin IX 28 90 = ve at ao a los 9, 8 au Pin ain no slip condit ( free stream veliking, (zero shear stres at edge of boundary layer) y = 8 Vx= ve si a₁8 = I FIN velocity profil put in Von Karmen integral solution. 9₁ ماد EN F/S =
obe
So
20
for
fdf
8*
8 = 309x
Ve
(3
S(x)
3
15 3
clas
"1
+
Je
8 = 3 X1-836
x
Adve
1.836
du
5.477
• fot
jove
To = 2 μ Ve
&
F
8(n)
82
14
5-4777
JRen
Ano a
152x
Ve
ги не
зхувь
v₂ = 1₂
Dx
Ren= V₂ x
5
Ve
Am Ⓒ deag
3/2
2 μ Ve
5-58 Jоn
Transcribed Image Text:obe So 20 for fdf 8* 8 = 309x Ve (3 S(x) 3 15 3 clas "1 + Je 8 = 3 X1-836 x Adve 1.836 du 5.477 • fot jove To = 2 μ Ve & F 8(n) 82 14 5-4777 JRen Ano a 152x Ve ги не зхувь v₂ = 1₂ Dx Ren= V₂ x 5 Ve Am Ⓒ deag 3/2 2 μ Ve 5-58 Jоn
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