(b) Using the grid below as a guide, draw a vector to represent the average force exerted on the object over the time interval from t = 0 to 4.0 s. Use a scale in which each grid square represents 1.0 N. Also verbally explain how you determined the average force, and show any calculations you make.
(b) Using the grid below as a guide, draw a vector to represent the average force exerted on the object over the time interval from t = 0 to 4.0 s. Use a scale in which each grid square represents 1.0 N. Also verbally explain how you determined the average force, and show any calculations you make.
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4 b please
![(a) Using the grid as a guide, draw a vector to represent the impulse exerted on the object over the time interval from t = 0 to 4.0 s. Use the same scale as in the diagrams above, and make the magnitude and direction of the vector accurate. Clearly show how the impulse is related to the momentum vectors given above. Also verbally explain how you determined the impulse vector.
[Image: Grid]
(b) Using the grid below as a guide, draw a vector to represent the average force exerted on the object over the time interval from t = 0 to 4.0 s. Use a scale in which each grid square represents 1.0 N. Also verbally explain how you determined the average force, and show any calculations you make.
[Image: Grid]
(c) During the time period between t = 6.0 s and t = 10.0 s, the same average force from part (b) acts on a different object that has half the mass of the original object. Using the grid below, draw a vector representing the change in momentum of the new object over this time period. Use a scale in which one square of the grid represents 1.0 kg m/s. Also verbally explain how you determined the change in momentum of the new object.
[Image: Grid]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F90ae1aab-f107-47ea-b140-00f7b3a4760d%2F3ba13173-a034-469b-8e68-134c768ea491%2Fsidssq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:(a) Using the grid as a guide, draw a vector to represent the impulse exerted on the object over the time interval from t = 0 to 4.0 s. Use the same scale as in the diagrams above, and make the magnitude and direction of the vector accurate. Clearly show how the impulse is related to the momentum vectors given above. Also verbally explain how you determined the impulse vector.
[Image: Grid]
(b) Using the grid below as a guide, draw a vector to represent the average force exerted on the object over the time interval from t = 0 to 4.0 s. Use a scale in which each grid square represents 1.0 N. Also verbally explain how you determined the average force, and show any calculations you make.
[Image: Grid]
(c) During the time period between t = 6.0 s and t = 10.0 s, the same average force from part (b) acts on a different object that has half the mass of the original object. Using the grid below, draw a vector representing the change in momentum of the new object over this time period. Use a scale in which one square of the grid represents 1.0 kg m/s. Also verbally explain how you determined the change in momentum of the new object.
[Image: Grid]

Transcribed Image Text:**Momentum Vectors Analysis**
At time \( t = 0 \), an object has momentum \(\vec{p}_1\), as shown in the diagram below on the left. The momentum vector is drawn on a grid, where each square represents 1 kg m/s. The vector \(\vec{p}_1\) has components 6.0 kg m/s to the right and 5.0 kg m/s downward.
At time \( t = 4.0 \, \text{s} \), the same object has momentum \(\vec{p}_2\), as depicted in the diagram below on the right. This vector is also drawn on a grid with the same scale. The vector \(\vec{p}_2\) has components 2.0 kg m/s to the left and 3.0 kg m/s upward.
**Diagram Explanation:**
- **Left Diagram (\(\vec{p}_1\)):** The vector is directed diagonally downwards and to the right, indicating a movement direction and force components. The vector shows a stronger horizontal component (6 squares to the right) compared to the vertical (5 squares downward).
- **Right Diagram (\(\vec{p}_2\)):** The vector is directed diagonally upwards and to the left. It indicates less horizontal force (2 squares to the left) and a smaller vertical component (3 squares upward) compared to \(\vec{p}_1\).
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