A salesperson makes four calls per day. A sample of 100 days gives the following frequencies of sales volumes.Number of SalesX0120314234TotalObserved FrequencyRecords show sales are made to 30% of all sales calls. Assuming independent sales calls, the number of sales per day should follow a binomial probability distribution. The binomial probability function presented in Chapter 5 isf(x) =n!x!(n-x)!*p*(1 − p)^ - *.ExpectedFrequencies(days)For this exercise, assume that the population has a binomial probability distribution with n = 4, p = 0.30, and x = 0, 1, 2, 3, and 4.(a) Compute the expected frequencies for x = 0, 1, 2, 3, and 4 by using the binomial probability function.30x = 2x = 3O x = 4Onone of the above332836100Do any of the categories have an expected frequency that is less than five? (Select all that apply.)Ox=0Ux=1 Before conducting a goodness of fit test, we must combine categories if necessary to satisfy the requirement that the expected frequency is five or more for all categories. What categories should we combine in order to satisfy this requirement?O x = 3 and x = 4O x = 2 and x = 3O x = 0 and x = 1O x = 0, x = 1, and x = 3O We don't need to combine any categories.(b) Use the goodness of fit test to determine whether the assumption of a binomial probability distribution should be rejected. Use a = 0.05. Because no parameters of the binomial probability distribution were estimated from the sample data, the degrees of freedom are k-1 when k is the number of categories.State the null and alternative hypotheses.O Ho: The population does not have a binomial distribution.H₂: The population has a binomial distribution.O Ho: The sample does not have a binomial distribution.H₂: The sample has a binomial distribution.O Ho: The population has a binomial distribution.H₂: The population does not have a binomial distribution.OH: The sample has a binomial distribution.H₂: The sample does not have a binomial distribution.Find the value of the test statistic. (Round your answer to three decimal places.)Find the p-value. (Round your answer to four decimal places.)p-value =State your conclusion.O Reject Ho. We conclude that the assumption of a binomial distribution can be rejected.O Reject Ho. We conclude that the assumption of a binomial distribution cannot be rejected.O Do not reject Ho. We conclude that the assumption of a binomial distribution can be rejected.O Do not reject Ho. We conclude that the assumption of a binomial distribution cannot be rejected.

Let X be the random variable that no. of sales. The observed frequencies are given as, x O 0 30…

Answered: (b) Use the goodness of fit test to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The inferential statistics is used to compare the sample sets and estimate the probability that they belong to truly different populations as opposed to be different just due to a random chance. P-value is the outcome of a statistical calculation. P stands for probability. The 'p-value' always between 0 and 1. The p-value of 0 means that an event never occurs, and p-value of 1 means that an event occurs always. In biomedical scinces, a p-value of 0.05 or less is usually considered significant (meaning the differences in the data are likely not due to chance, the sample(s) are not from the same population, and the observed differences are likely real). Value: 1 The p value of 0.03 indicates significant difference in biomedical sciences. True False Check Answer Tails is a statistical parameter that used in statistical significance testing. There are one-tailed and two-tailed options for statistical test. The one-tailed option is used when the hypothesis predicts not only difference…
A hospital administrator finds that the mean hospital stay for a sample of 77 women after childbirth is 3.1 days. She claims that the mean stay at her hospital is greater than the national average of 2.7 days. Assuming that the average at her hospital is the same as the national average, the probability of observing a sample with a mean of 3.1 days or more is 0.16. Formulate the null and alternative hypotheses. Then discuss whether the sample provides evidence for rejecting or not rejecting the null hypothesis. Assume a significance level of 0.05.
In a binomial distribution, n=8 and pie=0.36. Find the probabilities of the following events. a. X=5 b. X<=5 c. X>=6
2 Define the random variable, its type of distribution, and compute for the variable/measure that is being asked. You can follow the example below
A weighted coin has a 0.486 probability of landing on heads and a 0.514 probability of landing on tails. If you toss the coin 27 times, we want to know the probability of getting heads exactly 11 times.Consider a toss of heads as success in the binomial distribution.
A concern for many adults is that computers and the Internet are reducing privacy. A survey conducted by Peter D. Hart Research Associates for the Shell Poll was reported in the USA Today. According to the survey, 37% of adults are concerned that employers are monitoring phone calls. Use the binomial distribution formula to calculate the probability that out of five adults, exactly three are concerned that employers are monitoring their phone calls. Select one: O a. 1.85 Ob. 0.799 Oc. 0.201 d. 3.15
About 69% of people who are murdered knew the person who committed the murder. Suppose that Detective Williams's case load currently has 49 unsolved murders. Use a nomal distribution approximation to the binomial distribution to find the following probabilities: a. What is the probability that at least 30 of the victims among Detective Williams's case files knew their murderer? b. What is the probability that between 30 and 39 of the victims knew their murderer?
About 40% of all US adults will try to inflate an insurance claim to cover the deductible. Suppose that you work at an insurance company and just received 128 insurance claims. You are interested in the number of inflated claims. Is it fair to say this represents a binomial setting? Explain. Would it be reasonable to use the normal approximation? Explain. What is the probability that more than 80 of the claims are inflated?
Suppose that you take a sample of size 40 from a population that is normally distributed. Can the sampling distribution of x̄ be approximated by a normal probability distribution? What if the population was not normally distributed, can the sampling distribution of x̄ be approximated by a normal probability distribution?
Twenty-six percent of couples who plan to marry this year are planning destination weddings. Assume the variable is binomial. In a random sampleof 5 couples who plan to marry, find the probability of the following. Round intermediate calculations and final answers to three decimal places. At least 3 couples will have a destination wedding. P(at least 3 couples will have a destination wedding)=
I. Boston Children’s Hospital estimates that 90% of Americans have had chickenpoxby the time they reach adulthood.32(a) Suppose we take a random sample of 100 American adults. Is the use of the binomial distributionappropriate for calculating the probability that exactly 97 out of 100 randomly sampled Americanadults had chickenpox during childhood? Explain.(b) Calculate the probability that exactly 97 out of 100 randomly sampled American adults had chickenpoxduring childhood.(c) What is the probability that exactly 3 out of a new sample of 100 American adults have not hadchickenpox in their childhood?(d) What is the probability that at least 1 out of 10 randomly sampled American adults have had chickenpox?(e) What is the probability that at most 3 out of 10 randomly sampled American adults have not hadchickenpox?
A recent study showed that 71% of adults need some type of corrective lens (glasses or contacts). A. If I grab a 6 random people what is the probability that fewer than 4 need corrective lenses? B. If I take a random sample of 2000 people what is the mean and standard deviation of the number of people who need corrective lens? C. Use the normal approximation to the binomial to find the probability that I get 1375 or fewer people who need corrective lenses out of a random sample of 2000. Illustrate what you are finding on a sketch of the normal curve and show your work.

Recommended textbooks for you

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

Elementary Statistics: Picturing the World (7th E…

Statistics

ISBN:

9780134683416

Author:

Ron Larson, Betsy Farber

Publisher:

PEARSON

The Basic Practice of Statistics

Statistics

ISBN:

9781319042578

Author:

David S. Moore, William I. Notz, Michael A. Fligner

Publisher:

W. H. Freeman

Introduction to the Practice of Statistics

Statistics

ISBN:

9781319013387

Author:

David S. Moore, George P. McCabe, Bruce A. Craig

Publisher:

W. H. Freeman

SEE MORE TEXTBOOKS