(b) The UV-visible electronic absorbance spectrum of the following azo dye has an absorption maximum at 524 nm. Three Raman excitation wavelengths are available to obtain the spectrum of this molecule; 406 nm, 514 nm and 785 nm. Explain as fully as possible, the differences in the spectra that would be expected using each of these different excitation wavelengths, and why differences occur. State which wavelength would be the most appropriate, justify your answer. ΝΗΣ MeO N N N-NH Azo dye OMe
(b) The UV-visible electronic absorbance spectrum of the following azo dye has an absorption maximum at 524 nm. Three Raman excitation wavelengths are available to obtain the spectrum of this molecule; 406 nm, 514 nm and 785 nm. Explain as fully as possible, the differences in the spectra that would be expected using each of these different excitation wavelengths, and why differences occur. State which wavelength would be the most appropriate, justify your answer. ΝΗΣ MeO N N N-NH Azo dye OMe
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
Transcribed Image Text:(b) The UV-visible electronic absorbance spectrum of the following azo dye has
an absorption maximum at 524 nm.
Three Raman excitation wavelengths are available to obtain the spectrum of
this molecule; 406 nm, 514 nm and 785 nm.
Explain as fully as possible, the differences in the spectra that would be
expected using each of these different excitation wavelengths, and why
differences occur. State which wavelength would be the most appropriate,
justify your answer.
NH2
Meo
OMe
N
N-NH
Azo dye
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