(b)The strengths of stainless steel and carbon steel are being compared.Random samples were selected and tested. Table Q3 shows the tensilestrengths (in MPa) of the steel samples. Construct a 95% confidence intervalfor the difference between the means of the two steel samples.TABLE Q3: Tensile strength of stainless steel and carbon steelSteel TypeTensile Strength (MPa)Stainless Steel520456497425504448470Carbon Steel394410432380416

The table of steels types and their strengths are given as: Steel Type Tensile strength…

Answered: (b) The strengths of stainless steel…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A recent article published by the Wall Street Journal said the Cincinnati airport had the most expensive airfares among the largest airports in the US. While they had some statistics to support this statement, a statistician decided to investigate further. A sample of 46 flights originating in Cincinnati was selected, and the round-trip airfare for each flight was recorded. The sample data is summarized in the StatCrunch output below: With 98% confidence, we estimate the mean airfare for flights out of Cincinnati is between $ and $. (Round the limits of your interval to 4 decimal places.) The mean airfare nationwide was reported as $376 for a round-trip ticket. Does the interval found above support the claim that Cincinnati has airfares which are more expensive than other airports in the US? The interval does not support the claim because the entire interval is not above $376. We can't make this conclusion based on a confidence interval. The interval does not support this claim…
On average, adults spend approximately 5 hours per night in NREM (non-rapid eye movement) sleep. A sleep study selects a random sample of adults and gives them each a weighted blanket. They would like to know if using the weighted blanket changes the mean number of hours per night of NREM sleep. We want to test = 5 versus ≠ 5 where = the true mean hours of NREM sleep per night for adults who use a weighted blanket. A 99% confidence interval for the true mean hours of NREM sleep per night for adults who use a weighted blanket is (5.1, 5.8) hours. Based on the confidence interval, what conclusion would you make for a test of these hypotheses? The 99% confidence interval include as a plausible value, so we would H0. We convincing evidence that the true mean hours of NREM sleep per night for adults who use a weighted blanket 5 hours.
Researchers conducted a study to determine the effects of different types of alcohol on the peak alcohol concentration. In one part of the study, the researchers gave 15 randomly select males a controlled volume of vodka and monitored the subjects' alcohol concentration following the period of consumption. The legal limit for driving is 80 mg/dL (milligrams per deciliter of blood). A hypothesis test was conducted to see if the mean peak alcohol concentration from drinking vodka was different from the legal driving limit. This was reflected in the null and alternative hypotheses ?0:??1:?=80 mg/dL≠80 mg/dL The researchers required their results to be statistically significant at a level of ?=0.10. The mean peak alcohol concentration of the participants after drinking a controlled volume of vodka was 77.4 mg/dL with a standard deviation of 17.25 mg/dL. Determine the confidence interval that corresponds to the ?‑test. Give the lower and upper bounds precise to two decimal places
A small business wanted to estimate the mean income from their customers. They took a sample of 256 customers which yielded a sample mean of $71,250 with a standard deviation of $5,800 . What is the 90% confidence interval estimate for the population mean income of their customers.
The two, box and whisker diagrams below show the percentage marks obtained by two Grade 12 classes. Each class has 26 learners. Class A Class B O 10 20 30 40 50 60 70 80 90 100 The percentage marks for Class A, arranged in order, are given below: F: 58 60 62 62 63 65 65 66 66 66 66 67 69 70 71 73 73 90 [SASAMS database] 75 75 75 H 80 83 85 NOTE: Fis the lowest percentage mark H is a percentage mark between 75 and 80
What value of z would you use to calculate the 98% confidence interval for a population mean, given that you know the population standard deviation, the sample size and the sample mean of your sample?
We have developed a new drug used to reduce fever and want to test its efficacy. Ten ER patients who are running a fever agree to take the new drug instead of the traditional treatment. Their temperatures are taken before the drug is administered and 30 minutes after taking the drug. The results are recorded in the Excel file below. Use the data to construct and interpret a 99% confidence interval for the mean change in temperatures of patients after taking this drug using Excel. Be sure to include any explanation necessary along with a sentence that explains what the interval means. First Temp Second Temp 100.1 98.9 101.3 99.1 102.1 99.2 102.7 99 101.9 98.7 100.8 98.6 103.1 99.4 102.5 99.2 103.5 100.1 101.7 99.2
You want to estimate the mean weight of quarters in circulation. A sample of 60 quarters has a mean weight of 5.682 grams and a standard deviation of 0.061 gram. Use a single value to estimate the mean weight of all quarters. Also, find the 95% confidence interval for the average weight of all quarters. The estimate for the mean weight of all quarters is (Round to three decimal places as needed.) grams. Find the 95% confidence interval for the mean weight of all quarters. grams < p< grams (Round to three decimal places as needed.)
Please help with 1 a,b,c,d,e, and f.
A random sample of 50 CSCC students are surveyed to determine what percent of our students are first-generation college students. The results showed that 16 of the students identify as first-generation college students. show your work What is the sample proportion of first-generation college students at CSCC? Is this an example of a parameter or a statistic? Explain.
The mean score on the math portion of the ACT for the year 2000 is μ = 20.7. A sample of 20 students in a local school district had a mean of 22.95. Using the sample, a 95% confidence interval estimate for the mean is (20.76, 25.14). State the point estimate for the mean ACT score for students. Based on this sample information , do you believe that the local students have a mean different from the general population? Why? 22.95 is in the center of the interval. The means are definitely not different. 22.95 is just outside the 95% confidence interval. Can't say the means are really different. 22.95 is not equal to 20.7. The means are definitely different. 20.7 is just outside the 95% confidence interval. Can't say the means are really different.
I want to estimate the population mean number of times that adults eat breakfast in a week. I spoke with 12 coworkers, and the numbers were 7, 5, 5, 7, 2, 3, 7, 5, 1, 0, 7, 6. Calculate a 95% confidence interval for the population mean (round 3 decimal places).

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