b) The following readings were taken with a level and 4m staff. Draw up a level book page and reduce the Levels by Height of Collimation Method. 0.578 BM (58.250m), 0.933, 1.768, 2.240, (2.005 and 0.567) CP, 1.888, 1.181, (3.679 and 0.612) CP. 0.705, 1210. Apply Check

b) The following readings were taken with a level and 4m staff. Draw up a level book page and reduce the Levels by Height of Collimation Method. 0.578 BM (58.250m), 0.933, 1.768, 2.240, (2.005 and 0.567) CP, 1.888, 1.181, (3.679 and 0.612) CP. 0.705, 1210. Apply Check

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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QUESTION 1 A line of levels is run from BM1 to BM2 that is 8 km long. Elevation of BM1 and BM2 was found out to be 155.50, and 142.94 m, respectively. The average backsight and foresight distances were 148, and 169, respectively. Determine the corrected elevation of BM2 considering the effect of curvature and refraction. HINT: effect of curvature and refraction occurs on each rod reading. NOTE: answer in two decimal places
Determine the correct horizontal distance of AEwhen it was measured AB = 45m, BC= 38m, CD= 55m, DE =42.58, with difference of elevation per measurement as follows: 0.3m, 0.55m, 0.45m, 0.35m
5-23 Prepare a set of profile leveling notes for the data listed and show the page check. All data is given in feet. The elevation of BM A is 287.52, and the elevation of BM B is 272.20. Rod readings are: BS on BM A, 2.86; intermediate foresight (IFS) on 1+00, 3.7; FS on TP1, 10.56; BS on TP 1, 11.02; intermediate foresight on 2+00, 8.7; on 3+00, 6.5; FS on TP 2, 9.15; BS on TP 2, 4.28; intermediate foresight on 3+64, 3.5; on 4+00, 4.2; on 5+00, 6.4; FS on TP 3, 8.77; BS on TP 3, 4.16; FS on BM B, 9.08. SHOW WORK Answer: Math check= 272.28 Misclosure= 0.08 Correction= -0.02 per station
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