b)    Q1 × Q2 = _C^2 (c)    Solve for Q2 and Q1 using the two equations you got in part (a) and part (b).  (c) {Q1,Q2} = _C

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Two point-charges Q1 and Q2 are 3.4 m apart, and their total charge is 28μC. If the force of repulsion between them is 0.1454 N, what are magnitudes of the two charges by following the steps below?

Use Coulomb's Law to calculate the product of the two charges.

(b)    Q1 × Q2 = _C^2

(c)    Solve for Q2 and Q1 using the two equations you got in part (a) and part (b). 

(c) {Q1,Q2} = _C

(a) Q, + Q2 = 2.8 × 10-5
Use Coulomb's Law to calculate the product of the two charges.
(b) Q, x Q2 = 2.31 × 10-10|
XC-
(c) Solve for Q2 and Q, using the two equations you got in part (a) and part (b). Hint: There are two
possible solutions.
Enter the answer with curly brackets as {Q1,Q2} Wwhere Q, is the smaller charge and Q2 is the larger
charge.
(c) {Q1,Q2} =
XC
Transcribed Image Text:(a) Q, + Q2 = 2.8 × 10-5 Use Coulomb's Law to calculate the product of the two charges. (b) Q, x Q2 = 2.31 × 10-10| XC- (c) Solve for Q2 and Q, using the two equations you got in part (a) and part (b). Hint: There are two possible solutions. Enter the answer with curly brackets as {Q1,Q2} Wwhere Q, is the smaller charge and Q2 is the larger charge. (c) {Q1,Q2} = XC
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