A test charge of +2μC is placed halfway between a charge of +6μC and another of +4μC separated by distance 2d = 13 cm. The free body diagram of q2 from Part 1 should look like this: The force on q2 due to q1 is repulsive and acts to the right. The force on q2 due to q3 is repulsive and acts to the left.?3→2>?1→2?3→2>?1→2because q3>q1. (a) Calculate the force on the test charge by the +6μC charge. A test charge of +2µC is placed halfway between a charge of +6μC and another of +4µC separated bydistance 2d = 13 cm.+4uC9₁ = +4 µCdThe free body diagram of q₂ from Part 1 should look like this:+2μCF3-2✔Ndq2 = +2 μCF₁-2+6μСXThe force on q2 due to q₁ is repulsive and acts to the right. The force on q2 due to q3 is repulsive andacts to the left.F3-2 > F12 F3→2 > F1→2q3 = +6 μCbecause 9391.(a) Calculate the force on the test charge by the +6µC charge.Hint: The force in the positive x-direction is positive and the negative x direction is negative.N(b) Calculate the force on the test charge by the +4µC charge.N(c) Calculate the net force on the test charge by both the charges.

We are given 2 charges. Both are positive. We keep a test charge in between them This test charge is…

A test charge of +2μC is placed halfway between a charge of +6μC and another of +4μC separated by distance 2d = 13 cm. The free body diagram of q2 from Part 1 should look like this: The force on q2 due to q1 is repulsive and acts to the right. The force on q2 due to q3 is repulsive and acts to the left. ?3→2>?1→2?3→2>?1→2 because q3>q1. (a) Calculate the force on the test charge by the +6μC charge.

A test charge of +2μC is placed halfway between a charge of +6μC and another of +4μC separated by distance 2d = 13 cm. The free body diagram of q2 from Part 1 should look like this: The force on q2 due to q1 is repulsive and acts to the right. The force on q2 due to q3 is repulsive and acts to the left. ?3→2>?1→2?3→2>?1→2 because q3>q1. (a) Calculate the force on the test charge by the +6μC charge.

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