2022.02.14 21:27III.If the two vectors are parallel to each other, then the magnitude of cross product of two vectors isa) 1VECTORSb) 0 (żero)c) both a and biv.d) undefinedThe magnitude of the vector product of two vectors A and B may be [MAQ]a) greater than ABc) less than ABb) equal to ABd) zeroV.If PxQ=0 and ŌxR=0, then P×R is equal toa) zerob) PRsin 0c) PR cos 0d) PQ tan 0GOLD PACKAGE O7.A force F = 4i -5ĵ+3kacts at a point r = i-2 j+3k . The torque acting about a point7, = 3i - 2)- 3k isb) 30i + 30 +10ka) 42î + 30j- 6kd) 0c) 42i – 30j+ 6k1 8.(AxB)+(BxA) is equal tod) 2(Ã+B)c) 0b) A B²a) 2AB1 9.The area of the parallelogram whose adjacent sides are given by a = 3i – j+ 2k and b= i+4j-6k is[Note: area of the parallelogram is axb]614 squnitsGt) 32 sq unitsc) 573 squnits 7.A force F = 4i– 5î+3& acts at a point =i- 2j+ 3k · The torque acting about a point%3D+12ritrzb) 30i+30 j+10k5 = 3i – 2j- 3k is[ ]%3D|a) 42î + 30j– 6kc) 42î – 30j + 6kd) 0

Given: F⇀=4i^-5j^+3k^r1⇀=i^-2j^+3k^r2⇀=3i^-2j^-3k^

b) PR sin e c) PR Cos 0 d) PQu GOLD PACKAGE O 7. A force F = 4i -5j+3k acts at a point =i-2j+3k. The torque acting about %3D = 3i - 2)-3k is %3D a) 42î + 30j - 6k b) 30i + 30 j+10k d) 0 c) 42i - 30j+ 6k (AXB)+(BxA) is equal to 8.

b) PR sin e c) PR Cos 0 d) PQu GOLD PACKAGE O 7. A force F = 4i -5j+3k acts at a point =i-2j+3k. The torque acting about %3D = 3i - 2)-3k is %3D a) 42î + 30j - 6k b) 30i + 30 j+10k d) 0 c) 42i - 30j+ 6k (AXB)+(BxA) is equal to 8.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

The force of magnitude F = 141 lb acts along the edge of the triangular plate. Determine the moment of Fabout point O. The moment is positive if counterclockwise, negative if clockwise. 22" 12" F = 141 lb Answer: Mo = i Ib-in.
14 - A force with F = -8 i +6 j N acts on a particle whose position vector r = 3 i +4 j m. What is the torque acting on the particle relative to the centre? a) 30Nm B) 10Nm NS) 40Nm D) 50Nm TO) 60Nm
Depicted below is a cantilever beam that is being subjected to a 13.5 N Force Couple. 13.54 13,5N 7a) What is Magnitude of the Moment about point A if L = 6.0 meters and d = 2.25 meters? Magnitude = N-m. 7b) Does the couple cause a positive Moment about point A, or does it cause a negative Moment about point A? Which one - Positive or Negative? 7c) What is Magnitude of the Moment about point A if L was increased to 8.8 meters instead of 6.0 meters but d remained equal to 2.25 meters? Magnitude = N-m.
A wheel with moment of inertia 3.00 kg x m^2 has a net torque of 3.50 Nxm applied to it. What angular acceleration does it experience? A) 1.17rad/s^2 B) 0.857 rad/s^2 C) 3.50 rad/s^2 D 3.00 rad/s^2
The angular acceleration of a body = 3t2. What will be its speed at t=10s, if initial speed = 10rad/s? a) 1010 rad/s b) 300 rad/s c) 1310 rad/s d) 1000rad/s
4: A young man was jumping on a diving board with a length of 2.44 meters. If the force he exerted on the board is 60 Newton at a 20 degree angle, what is the torque applied on the fixed end of the board "point O"? A: 76 TニモX 6ON B: 56 app C: 20 29 D: 50 2.44M SUH CAtH TDA de problem 4 above, what will the direction of the torque be? 1orizontal
2. Given a displacement F = 4.0m 1 + 1.0m ĵ + 1.0m K, and a force F = 7.0N 1 +2.5N Ĵ- 5.0N K Find the torque.
Calculate the net torque about point O for the three forces (F₁=15.7 N, F₂=17.8 N and F3-20 N) applied on the rod as shown in the figure, where =25.2°. The rod and all forces are in the plane of the page. Assume the z-axis to be the axis perpendicular to the page. -12.0 m- 13.00 m 90.0⁰ 00 F₁ -4.00m- F2 10.3 m.N, about the z-axis 147 m.N, about the z-axis -66.5 m-N, about the z-axis 308 m.N, about the z-axis F3
A 5.0 kg block travels around a 0.60 m radius circle with an angular velocity of 15 rad/s. Its angular momentum about the center of the circle is... Select one: a. 24 kg. m/s b. 27 kg. m'/s c. 30 kg. m/s Previous page mula Sheet, CA-2, T-3, AY Jump to... 20-21 Activate Win L Go to Settings to
Given the two vectors r and F shown above, choose the direction of the resulting torque vector. left swer Tries 0/2 right in Discussion Senc out up
for a thin rod2~L4 a Caleulake 2 if L=3M ĘM=4Kg b) Using this equation I=Sp? dM Calcucite the moment of inertia of a thin rod of Mass M and length L around theleft end which will beu L=0
(a) Calculate the force (in N) the woman in the figure below exerts to do a push-up at constant speed, taking all data to be known to three digits. (You may need to use torque methods from a later chapter.) N 0.88 m m = 56 kg CG W 1.46 m W Freaction (b) How much work (in J) does she do if her center of mass rises 0.180 m? (c) What is her useful power output (in W) if she does 24 push-ups in 1 min? (Should work done lowering her body be included? See the discussion of useful work in Work, Energy, and Power in Humans.)