B) Perform an ANOVA statistical analysis on the following set of data. Provide relevant conclusions based on the F vs. F(crit) and p-value versus an alpha value (confidence) of 0.05. Do this for the stat tests comparing the rows, columns, and relating cach subsection. 田 Percent Effectiveness Group 1 Drug 1 Group 2 75 58 68 56 71 61 75 60 Drug 2 66 62 70 60 68 59 68 68
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- Rhino viruses typically cause common colds. In a test of the effectiveness of echinacea, 32 of the 39 subjects treated with echinacea developed rhinovirus infections. In a placebo group, 81 of the 94 subjects developed rhinovirus infections. Use a 0.05 significance level to test the claim that echinacea has an effect on rhinovirus infections. Complete parts (a) through (c) below. Identify the test statistic. Test the claim by constructing an appropriate confidence interval. Based on the results, does echinacea appear to have any effect on the infection rate?The two, box and whisker diagrams below show the percentage marks obtained by two Grade 12 classes. Each class has 26 learners. Class A Class B O 10 20 30 40 50 60 70 80 90 100 The percentage marks for Class A, arranged in order, are given below: F: 58 60 62 62 63 65 65 66 66 66 66 67 69 70 71 73 73 90 [SASAMS database] 75 75 75 H 80 83 85 NOTE: Fis the lowest percentage mark H is a percentage mark between 75 and 80The table below summarizes baseline characteristics of patients participating in a clinical trial. a) Are there any statistically significant differences in baseline characteristics between treatment groups? Justify your answer. Characteristic Placebo (n = 125) Experimental ( n =125) P Mean (+ Sd. Age 54 + 4.5 53 + 4.9 0.7856 % Female 39% 52% 0.0289 % Less than High School Education 24% 22% 0.0986 % Completing High School 37% 36% % Completing Some College 39% 42% Mean (+ Sd. Systolic Blood Pressure 136 + 13.8 134 + 12.4 0.4736 Mean (+ Sd. Total Cholesterol 214 + 24.9 210 + 23.1 0.8954 % Current Smokers 17% 15% 0.5741 % with Diabetes 8% 3% 0.0438
- The data is presented in parallel format. Before running the ANOVA in Excel, you will need to put it into serial (column) format. You will need to create a categorical variable for the first factor (days) and for the second factor (time of day). This is a critical step.The data presented shows exam scores for students randomly assigned to the sections meeting on these days at these times of the day: Thursday Friday Morning Afternoon Morning Afternoon 70.878.15978.246.646.476.559.376.370 65.678.359.359.778.680.892.780.865.392.3 90.890.569.177.36977.558.677.877.558.6 63.372.854.254.472.166.26372.56672.2 Conduct a 2-way ANOVA. First, find the group means for each level of the factors. (Report answers accurate to 2 decimal places.)Days: MThursday=MThursday= MFriday=MFriday= Time of day: Mmorning=Mmorning= Mafternoon=Mafternoon= Report the results of the ANOVA for the main & interaction effects. (Report P-values accurate to 4 decimal places and…Q: Using the data (provided below this question) apply ANOVA to determine if the mean response for value for the dollar is the same for different types of cell phones. Use a 5% significance level if the problem doesn’t give an alpha. Note: Please only provide the t stat, p-value, and critical value, no need to explain the whole process. Gender Carrier Type Usage Signal strength Value for the Dollar Customer Service M AT&T Smart High 5 4 4 M AT&T Smart High 5 4 2 M AT&T Smart Average 4 4 4 M AT&T Smart Very high 2 3 3 M AT&T Smart Very high 5 5 2 M AT&T Smart Very high 4 3 5 M AT&T Smart Very high 3 4 4 F AT&T Smart Very high 3 2 3 F AT&T Smart Very high 4 3 4 M AT&T Smart Very high 3 3 1 M Other Smart Average 1 2 4 M Sprint Smart Very high 3 5 4 M Sprint Smart Very high 3 5 3 F Sprint Smart Average 2 5 4 F Sprint Smart Average 3 5 4 M Verizon Smart Average 4 3 3 F Verizon Smart Very high 4 3 2 M Verizon…Use the departure delay times and the arrival delay times to test the claim that there is a correlation between departure delay times and arrival delay times. Test for rank correlation with a 0.05 significance level. Click here to view the flight delay data. Click here to view the critical values of Spearman's rank correlation coefficient. Flight delay data .... Determine the null and alternative hypotheses for this test. Choose the correct answer below. O A. Hg: Ps =0 Departure Delay Arrival Departure Delay Arrival O B. Ho: Ps #0 H: Ps = 0 Departure Delay Arrival H: Ps #0 Delay Delay Delay - 36 -7 11 14 OC. Ho:r 0 H:r=0 O D. Ho: r =0 H:rg 40 -21 15 25 -33 10 -32 Determine the the correlation coefficient. - 5 32 13 4 12 16 -23 (Round to three decimal places as needed.) 3 14 -38 60 28 13 3 13 149 111 Determine the critical value(s) of the correlation coefficient, -38 -7 -35 - 3 -21 -23 23 - 2 -10 14 (Round to three decimal places as needed. Use a comma to separate answers as needed.)…
- A teacher would like to determine if quiz scores improve after completion of a worksheet. The students take a pre-quiz before the worksheet and then another quiz after the worksheet. (Pre-quiz score - Post-quiz score) Assume quiz scores are normally distributed. The grades for each quiz are given below. Use a significance level of a = 0.05. H₂: Hd = 0 Ha: Hd <0 pre-quiz 12 16 17 16 11 15 12 7 15 13 post-quiz 13 16 15 16 14 15 13 9 14 15 What is the test statistic? test statistic = (Report answer accurate to 2 decimal places.) What is the p-value for this sample? p-value= (Report answer accurate to 3 decimal places.) The correct decision is to Select an answer Conclusion: Select an answer that the worksheet improved quiz scores.Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"Researchers examined the bill color (in hue degree) of male and female zebra finches. Here are the summary statistics from the study. Sex N Mean Standard deviation Males 59 2.91 1.46 Females 60 7.42 2.48 How different are male and female zebra finches in bill color? The margin of error for a 95% confidence interval for the difference in mean bill color μF – μM (in hue degree) is
- Use Excel’s Data Analysis tool to conduct a multiple regression, using Risk of Stroke as the dependent variable, and all the rest of variables as independent variables. Choose confidence level at 99%. Risk of Stroke (%) Age Pressure Smoker (Yes=1) 12 57 152 0 24 67 163 0 13 58 155 0 56 86 177 1 28 59 196 0 51 76 189 0 18 56 155 1 31 78 120 0 37 80 135 1 15 78 98 0 22 71 152 0 36 70 173 1 15 67 135 1 48 77 209 0 15 60 199 0 36 82 119 1 8 66 166 0 34 80 125 1 3 62 117 0 37 59 207 1 Interpret the multiple coefficient of determination R-square. Compare the R-square of the simple linear regression and the R-square of the multiple regression, what does the differences in R-squares tell us? What does F-test for significance tell us?The following data were obtained an independent-measures research study comparing three treatment conditions. Use an ANOVA with α = 0.05 to determine whether there are significant mean differences among the treatments. TREATMENT I II III 2 5 7 N = 14 5 2 3 G = 42 0 1 6 ∑X^2 = 182 1 2 4 2 2 T 12 10 20 SS 14 9 10Please provide a clear and complete solution. Thank you very much.