(b) Let F(x) be "x is friendly," T(x) be "x learns a trick," and S(r) be "x is shy," where the domainconsists of all dogs.Every dog who is friendly learns a trick. Every dog is friendly or shy. Therefore, every dog who isn'tshy learns a trick. Write each of the following arguments in argument form (i.e., using propositions, predicates, quantifiers, andlogical operators). Then, use the rules of inference and the laws of propositional logic to prove that eachargument is valid. You must indicate the name of the rule used in each step of the proof.EXAMPLE: Let r be "I run" and let e be "I eat."If I run, then I eat. I run. Therefore, I run and I eat.hypothesishypothesisAnswer:1.rere2.rr3.e.. глеmodus ponens (1, 2)4.глеconjunction (2, 3)

Approach to solving the question:The core approach involves translating the natural language…

Answered: (b) Let F(x) be "x is friendly," T(x)…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Let the domain be the set of all people. Let: P(x): "x is a kind-hearted person". Q(x): "x is an honest person". Translate the following statement into English: Jæ (¬Q(x) ^ ¬P(x)) Chapter 3.2 on zyBooks O Every dishonest person is also not kind-hearted. Everyone is not-kind hearted nor honest O Someone is not kind-hearted nor honest. O Everyone who is not kind-hearted is also dishonest.
An argument is expressed in English below. The domain is the set of people attending a party. Every person who was late to the party left the party early. There is a person who was late to the party and was not happy. .. There is a person who left the party early and was not happy. The form of the argument is: x (P(x) → Q(x)) 3X (P(x) ^ ¬R(x)) .: 3x (Q(x) ^ ¬R(x)) Select the definitions for predicates P, Q, and R. P(x): Pick Q(x): Pick R(x): Pick
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Conway's Game of Life: This is a zero person game with the following rules: (see Wikipedia for example) Any live cell with fewer than two live neighbours dies, as if by underpopulation. Any live cell with two or three live neighbours lives on to the next generation. Any live cell with more than three live neighbours dies, as if by overpopulation. Any dead cell with exactly three live neighbours becomes a live cell, as if by reproduction. Remember the oscillator or blinker of 3 cells. You can also find this blinker on Wikipedia. 1 21 1 2 1 21 3. 4 6 4. 6. 4 8. 9 8 9 #1 #2. #3 5. Consider now these 3 creatures at stage 1: Show how they look like in the next two stages: stage 2 and stage 3. Explain how you get the answers Creature 1 Creature 2 Creature 3 (here creature 1 is the blinker of 3 cells, horizontally; creature 2 consists of two adjacent cells, creature 3 consists of 4 adjacent cells horiztonally) ww (d) Creature 1 (10%), (e) Creature 2 (8%), (f) Creature 3 (20%)
The wolf-goat-cabbage ProblemDescription of the problem: There is a farmer who wishes to cross a river but he is not alone. He also has a goat, a wolf, and a cabbage along with him. There is only one boat available which can support the farmer and either of the goat, wolf or the cabbage. So at a time, the boat can have only two objects (farmer and one other). But the problem is, if the goat and wolf are left alone (either in the boat or onshore), the wolf will eat the goat. Similarly, if the goat and cabbage are left alone, then goat will eat the cabbage. The farmer wants to cross the river with all three of his belongings: goat, wolf, and cabbage.Complete the state space of this problem. The green state is valid state (you should expand it until to reach the goal state) and orange state is invalid state (you should not expand it).• w: wolf• g: goat• c: cabbage• f: framer• ||: rive.
please do it ASAP... I'll give you up thumb definitely
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Let the domain be the set of all animals. Let P(x, y) be the predicate "x is a y". Determine if the following statement is true or false: P( Dog, Mammal) Chapter 3.1 on zyBooks O True O False
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Let P(x) = "x passed the class". Let S(x) = "x studied". Let L(x) = "x got lucky". Which statement below means "Everyone who passed the class either studied or got lucky"? OVx ((P(x)→ S(x)) V L(x)) None of the other answer here listed is correct. OVx( P(x)→ S(x)) V L(x) OVx ((S(x) V L(x)) → P(x)) OV (P(x) → (S(x) v L(x)) ) OV (L(x) V (P(x) → S(x)))

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