B) In a sample of n = 50 people who recently received parking tickets, 36 were olderthan 25 years and the other 14 were age 25 or younger. Is the age distribution for thissample significantly different from the distribution for the population of licenseddrivers? Use a = .05.1. State the alternative hypothesis and null hypothesis2. Calculate the degrees of freedom (df) for chi-square.3. Using an a = .05, what is the critical value for chi-square (xcrit)?4. Calculate chi-square (x²) and provide a statement with words about your decision5. Write a sentence demonstrating how the results from the hypothesis test would appearin a research report.%3Dke the

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Answered: B) In a sample of n = 50 people who…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The yield per tract in a certain region of farmland is known to have a populationstandard deviation of 13 bushels. Using the old seed variety, the population mean yield μwas 39 bushels. A farmer tests a new seed variety on a random sample of 36 tracts, andfinds a sample mean yield of 45.2 bushels. Is the population mean yield using the newseed variety different from 39? Use α= 0.10.a. State the null hypothesis . __________________State the alternative hypothesis.____________________b. Find the test statistic. _____ c. Find the P-value for the test. _____________
In the US, 46.6% of all people have type O blood, 39.6% have type A blood, 10% have type B blood and 3.8% have type AB blood. A researcher wants to see if the distribution of blood type is different for millionaires. The table below shows the results of a random sample of 803 millionaires. What can be concluded at the significant level of ALPHA = 0.01. Round answers to 4 decimal places.1) State the hypotheses: 2) You drew 803 samples, and the observed frequencies are recorded below. Find the expected values. Blood Type ObservedFrequency ExpectedFrequency O 374 A 297 B 73 AB 59 The test-statistic for this data = The p-value for this sample = The p-value is greater than � less than (or equal to) � 3) Base on this, we should hypothesis As such, the final conclusion is that... Based on the sample data, there is sufficient evidence to claim that the distributions of blood types are not the same between the general population and the millionaires at…
If chi-square is NOT statistically significant with a sample size of 100 and sample size is increased to 1,000, the new chi-square: a. will have the same likelihood of being statistically significant than the previous chi-square b. cannot tell until the new chi-square is calculated c. will be less likely to be statistically significant d. will be more likely to be statistically signficant
A researcher was doing a study for a new Coronavirus Drug and conducted a hypothesis test like this one: H0: μ = 18 Ha: μ ≠ 18 a. What type of test is this? left-tailed right-tailed two-tailed b. She obtained a test statistic of 0.75, with a p-value of 0.4648. So she concluded that her true mean must be equal to 18. Is this interpretation correct? Yes No Why or why not?
The next six questions refer to the following scenario: A random sample of 25 students were asked to self-identify as "statistics-lovers" or "statistics-adorers." 16 students self-identified as "lovers" and 9 students as "adorers." Below table summarizes the mean of a statistics test and standard deviation that was given after the self-identification. Test the following hypothesis at alpha=5% (0.05). HO: Mean Statistics Lovers = Mean Statistics Adorers HA: Mean Statistics Lovers Mean Statistics Adorers You can assume equal variance.
Suppose that having a widow's peak was a dominant trait (W) compared to not having a widow's peak (w). In a sample size of 30 students, 15 were observed to have a widow's peak and 15 did not have a widow's peak. The expected frequency of a widow's peak is 75% chance of getting it and a 25% chance of not getting it. Perform a chi square analysis to see if the data above agrees with the predicted outcome.
A one-sample z-test compares a sample with 50 participants with mean 83 to a population with mean 80 and standard deviation 10. What is the effect size d? 0.1 0.3 0.5 0.7

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