(b) he following readings were taken in two sets of tests (under normal load N= 390 N and N2= 750 N) using a shear box of 60 mm x 60 mm in cross-sectional area containing a specimen of dry sand: i. Plot the vertical displacement against the horizontal displacement ii. Plot the shearing resistance against horizontal displacement iii. Determine the peak (o'peak) and critical state (o'cr) angle of internal frictions. iv. Explain what is dilatancy and determine the angle of dilation (y) in both tests. TEST 1 Normal Load P 390 N Horizontal T (kN) T (kPa) Vertical displacement displacement (mm) 0. (mm) 0.1615 -0.030 0.258 -0.020 3 0.291 0.140 4. 0.276 0.348 0.239 0.437 6. 0.2325 TEST 2 0.462 Normal Load

(b) he following readings were taken in two sets of tests (under normal load N= 390 N and N2= 750 N) using a shear box of 60 mm x 60 mm in cross-sectional area containing a specimen of dry sand: i. Plot the vertical displacement against the horizontal displacement ii. Plot the shearing resistance against horizontal displacement iii. Determine the peak (o'peak) and critical state (o'cr) angle of internal frictions. iv. Explain what is dilatancy and determine the angle of dilation (y) in both tests. TEST 1 Normal Load P 390 N Horizontal T (kN) T (kPa) Vertical displacement displacement (mm) 0. (mm) 0.1615 -0.030 0.258 -0.020 3 0.291 0.140 4. 0.276 0.348 0.239 0.437 6. 0.2325 TEST 2 0.462 Normal Load

Principles of Geotechnical Engineering (MindTap Course List)

9th Edition

ISBN:9781305970939

Author:Braja M. Das, Khaled Sobhan

Publisher:Braja M. Das, Khaled Sobhan

Chapter12: Shear Strength Of Soil

Section: Chapter Questions

Problem 12.18P

See similar textbooks

Related questions

Q: An aircraft is flying at a ground speed of 200 km/h. The focal length of the camera is 200mm. The…

Q: Solve the following systems: (1): 14x – 2y - 4z = 0 %3D 18x – 2y - 6z = 0 4x + 8y – 14z = 0 (2): 4X2…

Q: In Two peg test, if the observed rod reading on a rod held at point A with the instrument is stil…

A: The illustrated figure of two peg test is shown in figure below

Q: When does measurement error occur

Q: DETERMINE THE FOLLOWING; A. CENTROID OF THE CROSS-SECTION B. SECOND MOMENT OF AREA OF THE STRONGER…

A: A Section of structure member is given belowNeed to find1- Centroid of the section2- second moment…

Q: The focal length of a concave mirror is 10 cm and the object distance is 15cm. Determine (a) the…

A: Note - Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the…

Q: Determine the Reactions 10 k 6 k В DO 20 ft MN lb/ft A 30 ft 15 ft 10 ft 10 ft-

Q: 1. Locate the centroid of the shaded area figure shown. Yo 1ft 3 ft 2 ft 9 ft 6 ft -Xo

Q: Describe the basic principles of dilatometer testing

A: Dilatometer test: This is an flat plate dilatometer test we conduct this test as in situ test. The…

Q: Two towers, A and B, standing horizontal ground, vertically on a

Q: How the penetrometer operates on the surface?

A: Penetrometer Penetrometer is a device that is used to find the strength of soil or other materials.…

Q: For a compound differential manometer in fig given below calculate (PA-PB)?

A: To find pressure difference between point A and B

Q: ample Problem 5| A cast-iron beam carries the loads shown. If f;s20 IN/m² and fe<80 MN/m² , compute…

Q: mpletion Status: Two cables suspending a 100 kg object. The cables are at different angles from the…

A: Given Weight of block = 100kg Angles = theta = 35⁰ theta = 42⁰

Q: Importance of Acoustic bridge inspection

A: Bridge inspection is very important for the public and owner or the safe use of the structures…

Q: Determine the magnitude of the projected component r₁ along r₂ and the projection r₂ along r₁. 7₁ =…

A: Given: Required : Magnitude of projection of r1 along r2 and r2 along r1

Q: Solve dy _х-2y ; у (1) %3 -1 %D dx

Q: The term perception and reaction time (PRT) describes the period between the occurrence and the…

A: Brief concept- Perception and reaction time (PRT)- It is a very important aspect that needs to be…

Q: A W 12 x 65 steel section is used as a compression member. It is 8 m long, pinned connected at each…

A: The given data is shown below: A=11229 mm2rx=132 mmry=73 mmFy=382 mm

Q: Static feature constraint method for piezoelectric tiles in a shopping mall

A: A static feature constraint method for piezoelectric tiles in a shopping mall involves designing and…

Q: 1. Locate the centroid of the shaded area figure shown. 3 ft 2 ft 6 ft 1 ft 9 ft

Q: A W 12 x 65 steel section is used as a

Q: Determine the groundwater infiltration rate for a new four-lane pavement with the following…

A: Concept: The process by which the water present on the ground surface enters the soil is referred to…

Q: 1. A rectangular reinforced concrete beam with width of 300mm and effective depth of 600mm is…

Q: Difference betwen Sciemic retlection and repraction:

A: Seismic refraction is commonly limited to mapping bedrock depths and rippabilities at depths less…

Q: An accidental or compensating error can be eliminated by proper procedures. True False

A: Accidental or Compensating Error- It is that type of error which happens by mistake due to several…

Concept explainers

Types of Composite

Composite materials are formed by merging two components that have different chemical and physical properties. The merged output is termed as a composite, whose properties are completely different from the individual components. Composite materials also have better strength than the individual components.Composite materials usually have two main parts, reinforcement material, and matrix material. The matrix material acts as a binder and surrounds the fiber of another material that bears a much higher strength. This material is known as the reinforcement material. The matrix materials are usually high-strength additives resins, while the fibers of the reinforced material can be random, oriented, and in a mat format.Composite materials are also known as fiber-reinforced composite polymers because they are composed of the polymer matrix which is reinforced to laboratory-created fibers or naturally occurring fibers, such as glass fibers, carbon fibers, or aramid fibers. Under the application of external loads, the matrix material absorbs and transfers the loads to the fibers, these fibers in return provide good compressive strength, tensile strength, and stiffness to the fiber-reinforced composite materials.Depending upon the matrix and the reinforcement material, different properties can be induced to the fiber-reinforced composite materials, including good corrosion resistance properties. The most common matrix material is the resin while the glass fibers act as the reinforcement material. Strong fibers provide strength and stiffness to the composite materials while, a soft and flexible resin provides shape to the composite materials.

Question

Test 1 amd test 2 are image 1 and image 2

0.462
TEST 2
Normal
Load
P=750 N
Horizontal
T (kN)
T (kPa)
Vertical displacement
displacement
(mm)
(mm)
0.2525
-0.090
0.4256
-0.070
3
0.5342
0.050
4.
0.5537
0.222
0.4322
0.300
6.
0.4200
0.320

(b) The following readings were taken in two sets of tests (under normal load N= 390 N
and N2 750 N) using a shear box of 60 mm x 60 mm in cross-sectional area
containing a specimen of dry sand:
i. Plot the vertical displacement against the horizontal displacement
ii. Plot the shearing resistance against horizontal displacement
iii. Determine the peak (o'peak) and critical state (o'er) angle of internal frictions.
iv. Explain what is dilatancy and determine the angle of dilation (y) in both tests.
TEST 1
Normal
Load
P 390 N
Horizontal
displacement
(mm)
0.
T (kN)
T (kPa)
Vertical displacement
(mm)
0.1615
-0.030
0.258
-0.020
3
0.291
0.140
4.
0.276
0.348
0.239
0.437
6.
0.2325
TEST 2
0.462
Normal
Load

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Step by step

Solved in 4 steps with 4 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Show solution. The answer must be A. 36.87 B. 14
2. A series of consolidated, undrained triaxial tests were carried out on specimens of a saturated clay under no backpressure. The test data at failure are summarized: Confining Pressure (kPa) Deviator Stress (kPa) Pore Water Pressure (kPa) 150 192 80 300 341 154 450 504 222 a. Draw the Mohr circles and find the cohesion and friction angles in terms of effective stresses. b. Compute Skempton’s A-parameter at failure for all three specimens. c. Is the soil normally consolidated or overconsolidated? Why? d. Another specimen of the same clay that was consolidated under a cell pressure of 250 kPa was subjected to a consolidated, drained triaxial test. What would be the deviator stress at failure?
Hello, can I get help in answering this question?
2. A sample of saturated clay of height 20 mm and water content 30% was tested in an oedometer. Loading and unloading of the sample were carried out. The thickness Hf of the sample at the end of each stress increment/decrement is shown in the table below. o: (kPa) H, (mm) 100 200 400 200 18.68 100 18.75 20 19.31 18.62 a. Plot the results as void ratio versus o'z (log scale). b. Determine Cc and Cr.
Triaxial tests performed on samples of aeolin sand. The failure conditions in terms of effective stress are (ov, 0h) = (515, 100), (1250, 200), (3500, 400), and (5325, 800) kPa. Using (s, t) space, determine the cohesion and friction angle. What is the orientation of the major principal stress with respect to the failure plane? Determine this graphically.
Question A sample of dry sand was tested in direct shear test apparatus under a normal load of 72 kg. The shear load required to fail the sample was found to be 36 kg. The angle of internal friction () will be:
complete pls
SITUATION 5: A sand sample is subjected to direct shear testing at it's (in - situ) water content. Two tests are performed. For one of the tests, the sample shears at a stress of 400 kPa when the normal stress is 600 kPa. From these data, 15. Determine the value of the apparent cohesion. c. 230 kPa d. 221 kPa а. 100 kPa b. 179 КРа 16. Determine the corresponding angle of internal friction. a. 22.65 degrees b. 26.57 degrees c. 32.54 degrees d. 18.43 degrees
A direct shear test is performed on a specimen of dry sand. The shear box is circular in cross-section with a diameter of 50 mm. The normal force imposed on the specimen is 250 N. Then shears when the shear force is 150 N. Determine the angle of internal friction of this sand.
Subject : Geotechnical Engineering Please I don't have much time... Kindly give me right solution... Urgent please
Please solve fully. Thank you
The table shows the results of a consolidated undrained (CU) test on a overconsolidated clay soil sample. Sample No Cell Pressure (kPa) Deviator stress at failure (kPa) Pore water pressure at failure (kPa) 1 15 20 10 2 30 25 15 For the given data, plot the effective stress Mohr's circles at failure. Estimate the effective shear strength parameters C' amd phi'.