how do i enter this formula in my calculator, when i enter that formula my calculator is giving me different values thanks b)=>⇒ Vallage across capacitor at t =20/7Ve (I msec)твес=2005047 V38ecCurrent through capacitar atSc (Amber)msec=0.72080-15x120-15XI-0.36et==T80-msec,(08 (30000 XII m)180 Sin (30,000 × 17 m)x80ic (msec)-0.0316 A

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Answered: b) => ⇒ Vallage across capacitor at t =…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A tall building has a shadow of 100m on ground. An engineer used a meterstick to measure the building height indirectly. Using another meterstick, the shadow of the first stick was measured as 0.5m Find the building height.
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3) If two forces of 10,000 N are continuously rotating 1,000,000 shafts, the ball bearings and shaft thickness must be selected. The system should be drawn in 3D and proven to work safely. Please note that you must determine the dimensions of the system and the shaft material and code yourself. This question should only be answered if you are between 61 and 90 in the student list (#61-90). F Bearing ☑ ☑ ☑ ☑ Shaft F
2. Complete the table. This problem involves the power required to raise a mass a given distance in a given amount of time. (Round your answers for mass and energy to the nearest whole number.) (Round your answers for power to two decimal places.) 3 Click the icon to view the table to complete. 4 Click the icon to view the conversion table. 5 Click the icon to view the table of common derived units in the Sl system. 3: More Info 4: More Info 2 11 Q W (a) (b) (a) (b) Mass [bm] 220 Time 1 d = 24 h 1 h = 60 min Mass [Ibm 1 min = 60 s 3 1 yr = 365 d E 220 $ 4 Distance [ft] 1 kg = 1 slug = 14.5939 kg 1 slug = 32.2 lbm 15 Distance [ft] 15 35 Mass 2.205 lbm I R 35 % 5 I T Energy [J] Length 1 m = 3.28 ft 1 km = 0.621 mi 1 in = 2.54 cm 1 mi = 5,280 ft Energy [J] ^ 6 MacBook Pro Y & 7 Time [min] Energy 1 J = 0.239 cal = 9.48 x 10-4 BTU = 0.7376 ft lbf 1 kWh 3,600,000 J H 0.5 Time [min] 0.5 2 2 8 1 ( 20 Power [hp] 0.134 Power [hp] 0.134 Power 1 W 3.412 BTU/h = 0.00134 hp = 14.34 cal/min = 0.7376…

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b) => ⇒ Vallage across capacitor at t = 20/7 Ve (I msec) твес = 2005047 V 38ec Current through capacitar at Sc (Amber) msec = 0.720 80 -15x120 -15XI -0.36e t == T 80 -msec, (08 (30000 XII m) 180 Sin (30,000 × 17 m) x 80 ic (msec) -0.0316 A