b) Given the following instruction sequence: Line 01 02 03 04 05 06 07 MAIN: Instructions ORG MOV ADD DA ADD DA END 0000H A, #13H A, #25H A A, #37H A (i) Convert the instruction sequence into hexadecimal machine language. (ii) Explain what does the instruction "DA A" as in line 4 and line 6 do? Determine the content of the accumulator after executing line 4 and line 6 respectively.

b) Given the following instruction sequence: Line 01 02 03 04 05 06 07 MAIN: Instructions ORG MOV ADD DA ADD DA END 0000H A, #13H A, #25H A A, #37H A (i) Convert the instruction sequence into hexadecimal machine language. (ii) Explain what does the instruction "DA A" as in line 4 and line 6 do? Determine the content of the accumulator after executing line 4 and line 6 respectively.

Name: b) Given the following instruction sequence:Line01020304050607MAIN:In
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Description: b) Given the following instruction sequence:Line01020304050607MAIN:InstructionsORGMOVADDDAADDDAEND0000HA, #13HA, #25HAA, #37HA(i) Convert the instruction sequence into hexadecimal machine language.(ii) Explain what does the instruction "DA A" as in

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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3. Suppose M8=x and M9=y. After each instruction has been executed, what is the content of the location indicated in column 3? Fill the contents in the table. Address M1 Content MMR M8 R1 MMR M9 R2 Locations Register 1 Register 2 Accumulator M7 Content М2 M3 ADD R1 R2 М4 МАМ M7 M5 HLT M7
4. Write an instruction sequence that generates a byte-size integer in the memory location defined as RESULT. The value of the integer is to be calculated from the logic equation (RESULT) = (AL) · (NUM1) + (NUM2) · (AL) + (BL) Assume that all parameters are byte sized. NUM1, NUM2, and RESULT are the offset addresses of memory locations in the current data segment.
For each following, assume the Before values when the given instruction is executed. Give the requested After values. ; Before: RAX: 0A0A 0A0A 0A0A 0A0AH; R15: 1B1C 1B1D 1B1E 1B1FH XCHG EAX, R15 ; After: EAX, R15D
Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es. If applicable, determine the content of the destination after the execution of the instruction. Otherwise, NA. For physical address and content of the destination, use CAPITAL LETTERS,NO SPACE/S in between and NO need to include "H" or the unit. A - is for addressing mode type, e.g. directB - physical address/es e.g. 19000-19001 C - content of the destination after executione.g. if register: AX=1234 if memory (lower address first) : 12000=34;12001=12 GIVENDS = ACF7HSS = BAC9HDI = ECABHSI = ABAEHBP = BAD2HAX = 6FCBHBX = 7BCFHCX = 5CADHDX =D1BCHSP = 4FABH
Fill in the following table showing the results of the indicated instructions, using the register values shown. Also, show the OF and CF values AFTER the instruction executes. Show all results in hexadecimal. Show OF and CF as 0 or 1.
please translate this mips codes to the machine language
:Q1: Answer the following Write equivalent instruction sequences • using string instruction for the following: MOV AL, [DI] CMP AL, [SI] DEC SI DEC DI إجابتك Write equivalent instruction sequences • using string instruction for the following: MOV AL, [SI] MOV [DI], AL INC SI INC DI إجابتك State the purpose of the instructions CLD, • .STD, CLI, and STI إجابتك
What will be the value of AH (in Hexadecimal) after the execution of the following instructions: MOV AL,26 MOV AH,53 CMP AL, 20H JBE OVER ADD AL,AL ADD AH,AL OVER: ADD AH,22
I need original answer not plagiarised. So don't copy others'content they are wrong.
For the RISC-V assembly instructions below, what is the corresponding C statement? Assume that the variables f, g, h, i, and j are assigned to registers x5, x6, x7, x28, and x29, respectively. Assume that the base address of the arrays A and B are in registers x10 and x11, respectively. sub x30, x28, x29 slli x30, x30, 2 add x3, x30, x10 add x4, x30, x11 1w x30, 0 (x3) 1w x31, 0 (x4) add x30, x30, x31 sw x30, 16 (x11)
Determine the specific type of addressing mode (SMALL LETTERS only) and compute for the address/es. If applicable, determine the content of the destination after the execution of the instruction. Otherwise, NA. For physical address and content of the destination, use CAPITAL LETTERS,NO SPACE/S in between and NO need to include "H" or the unit. If the given register are fewer than required, just put zeroes in the most significant place. A -effective address B - physical address/es e.g. 19000-19001 C - is for addressing mode type, e.g. direct D - content of the destination after execution e.g. if register: AX=1234 EFFECTIVE ADDRES: PHYSICAL ADDRESS/ES: ADDRESSING MODE : CONTENT OF THE DESTINATION: if memory (lower address first): 12000=34;12001=12
Write content of the register AL as two hexadecimal digits (without any other symbols). Image: