Consider the following instruction: AND ( %1111_0000, AL ); After its execution, what will be true about the bits stored in AL? The four low-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL O The four high-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL O The four high-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL O The four low-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL O None of the choices presented are correct

Consider the following instruction: AND ( %1111_0000, AL ); After its execution, what will be true about the bits stored in AL? The four low-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL O The four high-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL O The four high-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL O The four low-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL O None of the choices presented are correct

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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What is the final result for AL and BL after executing the sequential mnemonic opcode/operand instructions? MOV AL, 00000110b MOV BL, 00000111b CMP BL, 00000101b JMP NEXT JZ EQUALZERO ΝEXT: ADD AL, BL NOP EXIT EQUALZERO: SUB BL, AL ΕXIT a. The final result for AL is 0E and for BL is FA. Ob. The final result for AL is 0D and for BL is 07. Oc. The final result for AL is 4D and for BL is EA. Od. The final result for AL is OF and for BL is FB.
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