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Consider the following instruction: AND ( %1111_0000, AL ); After its execution, what will be true about the bits stored in AL? The four low-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL O The four high-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL O The four high-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL O The four low-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL O None of the choices presented are correct

Consider the following instruction: AND ( %1111_0000, AL ); After its execution, what will be true about the bits stored in AL? The four low-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL O The four high-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL O The four high-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL O The four low-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL O None of the choices presented are correct

Database System Concepts
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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### Instruction and Question: **Consider the following instruction:** `AND( %1111_0000, AL );` **After its execution, what will be true about the bits stored in AL?** ### Options: - **Option A:** The four low-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL. - **Option B:** The four high-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL. - **Option C:** The four high-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL. - **Option D:** The four low-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL. - **Option E:** None of the choices presented are correct. ### Explanation: The bitwise AND operation between the byte `AL` and `1111_0000` will result in the lower four bits of `AL` (the low-order bits) being set to zero. This operation masks out the lower four bits of `AL`, since any AND operation with 0 results in 0. ### Conclusion: **Correct Answer:** Option A - The four low-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL.
Transcribed Image Text:### Instruction and Question: **Consider the following instruction:** `AND( %1111_0000, AL );` **After its execution, what will be true about the bits stored in AL?** ### Options: - **Option A:** The four low-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL. - **Option B:** The four high-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL. - **Option C:** The four high-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL. - **Option D:** The four low-order bits stored in AL are guaranteed to all be ones, regardless of the value originally held in AL. - **Option E:** None of the choices presented are correct. ### Explanation: The bitwise AND operation between the byte `AL` and `1111_0000` will result in the lower four bits of `AL` (the low-order bits) being set to zero. This operation masks out the lower four bits of `AL`, since any AND operation with 0 results in 0. ### Conclusion: **Correct Answer:** Option A - The four low-order bits stored in AL are guaranteed to all be zeros, regardless of the value originally held in AL.
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