b) From the graph in the Fig. 4, what will be the Current through the LED that will causes the LED to release an intensity of 4000 Lux
b) From the graph in the Fig. 4, what will be the Current through the LED that will causes the LED to release an intensity of 4000 Lux
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Transcribed Image Text:Relationship Between Current and Light Intensity
6-
y = Ax
A: 0.29 x 10° lux/mA
0-
20
40
60
Current (mA)
Figure 4 Light intensity as a function of current. A proportional relationship is
shown up to 20 mA, corresponding to 3.5 V.
H
4.
Light Intensity (x 10 * lux)
Transcribed Image Text:7) You have being provided with the LED the author used in
the experiment. You have a battery of 9Volts and you need
to find the resistor connected in series that will ensure that
the LED will release 4000 lux
R
led
V
led
b) From the graph in the Fig. 4, what will be the Current
through the LED that will causes the LED to release an
intensity of 4000 Lux
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