(b) Find the mechanical energy lost due to friction if Vf = 16.0 m/s < 20.7 m/s. Write Equation 5.12, substituting expressions for the kinetic and potential energies. Wnc = (KEf - KE;) + (PEf - PE¡) 1 5muj - 5mv; +mgyf – mgy; Substitute m = 58.3 kg, vf = 16.0 m/s, and v; = 0, and solve for Wnc: 1 G: 58.3 kg (16.0m/s)² + 0] Wnc [0 – 58.3 kg · (9.80m/s²) · 21.9 m] + = |-6256 Wnc X J Your response differs from the correct answer by more than 10%. Double check your calculations.
(b) Find the mechanical energy lost due to friction if Vf = 16.0 m/s < 20.7 m/s. Write Equation 5.12, substituting expressions for the kinetic and potential energies. Wnc = (KEf - KE;) + (PEf - PE¡) 1 5muj - 5mv; +mgyf – mgy; Substitute m = 58.3 kg, vf = 16.0 m/s, and v; = 0, and solve for Wnc: 1 G: 58.3 kg (16.0m/s)² + 0] Wnc [0 – 58.3 kg · (9.80m/s²) · 21.9 m] + = |-6256 Wnc X J Your response differs from the correct answer by more than 10%. Double check your calculations.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem (b):** Find the mechanical energy lost due to friction if \( v_f = 16.0 \, \text{m/s} < 20.7 \, \text{m/s} \).
Write Equation 5.12, substituting expressions for the kinetic and potential energies.
\[ W_{nc} = (KE_f - KE_i) + (PE_f - PE_i) \]
\[ = \frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2 + mgy_f - mgy_i \]
Substitute \( m = 58.3 \, \text{kg}, \, v_f = 16.0 \, \text{m/s}, \, \text{and} \, v_i = 0 \), and solve for \( W_{nc} \).
\[ W_{nc} = \left[\frac{1}{2} \times 58.3 \, \text{kg} \times (16.0 \, \text{m/s})^2 + 0\right] \]
\[ + \left[0 - 58.3 \, \text{kg} \times (9.80 \, \text{m/s}^2) \times 21.9 \, \text{m} \right] \]
\[ W_{nc} = \boxed{-6256} \, \text{J} \]
**Note:** Your response differs from the correct answer by more than 10%. Double check your calculations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3a74cc31-62f4-4982-89c3-ce8d7d2cfbb2%2Fc1853cc3-cc90-4419-ae62-fe6db9ee28de%2F1rjqvlg_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem (b):** Find the mechanical energy lost due to friction if \( v_f = 16.0 \, \text{m/s} < 20.7 \, \text{m/s} \).
Write Equation 5.12, substituting expressions for the kinetic and potential energies.
\[ W_{nc} = (KE_f - KE_i) + (PE_f - PE_i) \]
\[ = \frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2 + mgy_f - mgy_i \]
Substitute \( m = 58.3 \, \text{kg}, \, v_f = 16.0 \, \text{m/s}, \, \text{and} \, v_i = 0 \), and solve for \( W_{nc} \).
\[ W_{nc} = \left[\frac{1}{2} \times 58.3 \, \text{kg} \times (16.0 \, \text{m/s})^2 + 0\right] \]
\[ + \left[0 - 58.3 \, \text{kg} \times (9.80 \, \text{m/s}^2) \times 21.9 \, \text{m} \right] \]
\[ W_{nc} = \boxed{-6256} \, \text{J} \]
**Note:** Your response differs from the correct answer by more than 10%. Double check your calculations.
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